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Alika [10]
4 years ago
5

Question 1 (1 point) Which equation can be represented by a graph with a vertex at (1,3)?

Mathematics
1 answer:
madam [21]4 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

You have not provided the options to help us give you a specific answer.

If a quadratic function is written in the form

f(x) = a {(x - h)}^{2}  + k

Then (h,k) is the vertex, and 'a' is a constant.

For instance

f(x) = 5 {(x - 1)}^{2}  + 3

has vertex at (2,3).

Also, an absolute function in the form

g(x) = a  |x - h|  + k

has vertex at (h,k).

This means

g(x) =   |x - 1|  + 3

also has vertex at (1,3).

I hope this explanation is helpful.

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Solve the equation 4x+8y=12 for x
kondor19780726 [428]
4x+8y=12

x=2 

y = 1/2

Plug in each number

4(2)+8(1/2)=12
 
8+4=12

7 0
4 years ago
In Miron's class, there are 25 students. 3/5 of the students are boys. How many of the students in his class are boys?
Basile [38]

Answer:

15

Step-by-step explanation:

to find it we must do this equation:

(25/5) * 3

5 * 3 = 15

To check :

15/25 = 3/5

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0
3 years ago
Read 2 more answers
If Martin scored a 77 and an 83 on his last two quizzes, what was his quiz average ​
mihalych1998 [28]
His average is 80%. You take the two scores add them up and divide by the number of scores.
6 0
3 years ago
The coefficient of 2(3)(6) Q is
user100 [1]

Answer:

Coefficient of Q is 36.

Step-by-step explanation:

The coefficient means the constant term with the variable

Here, we need to  find the coefficient of Q

We have been given an expression:

2(3)(6)Q

The coefficient of Q is the simplified form of the constant terms given:

Multiply the terms to get the simplified form which is:

36Q

Hence, the coefficient of Q is 36.

3 0
3 years ago
Read 2 more answers
Can I have help with this please?
mamaluj [8]

Answer:

x+1+2x-6= 16

3x-5 =16

3x=16+5

3x=21

x=21/3

x= 7

VW= 2x-6 = 2(7) -6 = 14-6 = 8

5 0
3 years ago
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