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3 years ago

8

What is 378 times by 9

1 answer:

Korvikt [17]3 years ago

7 0

The answer for 378 x 9 = 3402

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The sum of two numbers is 64 . the larger number is 18 more than the smaller number. what are the numbers?

-BARSIC- [3]

64-18 is 46
46/2 is 23
23+18 is 41

Your #s are 21 and 43

8 0

3 years ago

Which equation represents a circle with a center at (2,-3) and a radius of 11

Verdich [7]

Answer:

x^2-4x+y^2+6y-108=0

Step-by-step explanation:

$The- equation- of- circle- with -center- at- (h,k) -and -a -radius- of- r -is: \\(x-h)^2 +(y-k)^2 = r^2\\h = 2 , \\ k = -3\\r = 11\\(x-2)^2+(y-(-3))^2 = 11^2\\(x-2)^2+(y+3)^2 = 121\\x^2-4x+4 +y^2+6y+9 = 121\\x^2 -4x+y^2+6y+4+9=121\\x^2 -4x+y^2+6y+13=121\\x^2 -4x+y^2+6y=121-13\\x^2 -4x+y^2+6y= 108\\x^2 -4x+y^2+6y-108 = 0$

8 0

3 years ago

Write an equation in slope-intercept form of the line having the given slope and y-intercept.

pychu [463]

Answer:

The answer to your question is y = 4/6x - 4

Step-by-step explanation:

Data

m = 4/6

P (0, -4)

slope-intercept form = ? y = mx + b where m is the slope and

b is the y-intercept

Formula

y - y1 = m(x - x1)

Substitution

y - (-4) = 4/6(x - 0)

Simplification

y + 4 = 4/6x

Result

y = 4/6x - 4

slope = 4/6 y-intercept = -4

7 0

3 years ago

Helppppp pleaseeeeeeeee

notka56 [123]

Answer:

Price 4 years from today: 887

9 years: 1008

just plug in the amount of years for t!

5 0

2 years ago

Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

$y=-x^2+6x-4$

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

7 0

4 years ago