So we know that $3 can buy 6 cans. So your tryna find tbe price for one can, so just divide $3 by 6 cans. You should get $2 for one can. If you know the linear equation, y=mx+b, m is the slope and what do you think the slope is? :) b is the y intercept so $2 is for how many cans? Your answer should be y=2x+1.
Answer:
Any c answer that fits 5
<c<37 is correct.
Step-by-step explanation:
Say the three sides of the triangle are
a
,
b
and
c
. Here,
a
=
16
and
b
=
21
. We must find the possible values of
c
.
Since
a
+
c
>
b
, we can input:
16
+
c
>
21
c
>
5
.
So the lower bound of
c
is everything above
5
.
We also know that
a
+
b
>
c
. Inputting:
16
+
21
>
c
37
>
c
.
So
c
must be less than, but not including
37
.
In conclusion, the side length
c
must satisfy the following inequality:
An aritmetic sequcne is represented as
![a_n=a_1+d(n-1)](https://tex.z-dn.net/?f=a_n%3Da_1%2Bd%28n-1%29)
where
an=nth term
a1=first term
d=common differnce, or how much each term increases by
n=which term
example
1,3,5, etc
first term is 1
common difference is 2 because it increases by 2 each time
so the formula would be
![a_n=1+2(n-1)](https://tex.z-dn.net/?f=a_n%3D1%2B2%28n-1%29)
if we had
5,3,1
first term s 5
common difference is -2 since it goes up by -2 each time
so formula is
![a_n=5-2(n-1)](https://tex.z-dn.net/?f=a_n%3D5-2%28n-1%29)
hope this helps
Answer:
−4.5x+4.7
Step-by-step explanation:
Answer:
x=-12 and -3
Step-by-step explanation:
The quadratic formula is
.
It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions. We will substitute a=1, b=15 and c=36.
![x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-15+/-\sqrt{(15)^2-4(1)(36)} }{2(1)}\\x=\frac{-15+/-\sqrt{225-144} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B%2815%29%5E2-4%281%29%2836%29%7D%20%7D%7B2%281%29%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B225-144%7D%20%7D%7B2%7D)
We will now simplify and solve.
![x=\frac{-15+/-\sqrt{81}}{2}\\x=\frac{-15+/-9}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-15%2B%2F-%5Csqrt%7B81%7D%7D%7B2%7D%5C%5Cx%3D%5Cfrac%7B-15%2B%2F-9%7D%7B2%7D)
x=-12 and x=-3