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lapo4ka [179]
4 years ago
15

Theobromine, C7H8N4O2, is a component of chocolate. It is mildly diuretic, is a mild stimulant, and relaxes the smooth muscles o

f the bronchi in the lungs. Because dogs metabolize it more slowly than humans, theobromine is very toxic to dogs.
If there are 0.064 g of theobromine in a 43 g chocolate bar, how many moles of theobromine are there?
a) 1.5 x 10−3 moles
b) 3.55181 x 10−4 moles
c) 3.6 x 10−4 moles
d) 12 moles
Chemistry
1 answer:
Ierofanga [76]4 years ago
8 0

Answer:

3.6\times 10^{-4} moles of Threobromine are present in chocolate bar

Explanation:

Molar mass of Theobromine = (7\timesmolar mass of C)+(8\timesmolar mass of H)+(4\timesmolar mass of N)+(2\timesmolar mass of O) = (7\times12g/mol)+(8\times1g/mol)+(4\times14g/mol)+(2\times16g/mol) = 180 g/mol

We know that, number of moles of a compound is the ratio of mass to molar mass of the compound.

So, 0.064 g of Threobromine = \frac{0.064}{180} moles of Threobromine = 3.6\times 10^{-4} moles of Threobromine

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Mr. Chem S. Tree added water to 250. ML of a 2.50 M NaOH solution, until the final volume was 500. ML. What is the new molarity
tresset_1 [31]

Answer:

molarity of diluted solution = 1.25 M

Explanation:

Using,          

C1V1 (Stock solution) = C2V2 (dilute solution)

given that

C1 = 2.50M

V1 = 250ML

C2 = ?

V2 = 500ML

2.50 M x 250 mL = C2 x 500 mL

C2 = (2.50 M x 250 mL) / 500 mL

C2 = 1.25 M

Hence, molarity of diluted solution = 1.25 M

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3 years ago
During the drying cycle, clothes soaked in liquid PERC at 300 K at 1 atm are tumbled in a stream of warm air at 330 K at 1 atm t
djyliett [7]
The answer is option A
6 0
3 years ago
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AleksAgata [21]

Answer:

A) (3.2g)

Explanation:

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3 0
3 years ago
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Identify the type of molecule shown in the picture
BlackZzzverrR [31]
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7 0
3 years ago
The two balanced equations (1) and (2) are for reactions in which gaseous carbon dioxide is produced from the combustion of (1)
V125BC [204]

Answer:

2.0 mol of oxygen are consumed.

Step-by-step explanation:

You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.

M_r:   28.0                 44.0

          CO  + ½O₂ ⟶ CO₂ + 67.6 kcal

m/g:   112

<em>Step 1</em>. Convert grams of CO to moles of CO

1 mol CO = 28.0 g CO

Moles of CO = 112 × 1/28.0

<em>Step 2.</em> Convert moles of CO to moles of CO₂.

The molar ratio is 1 mol CO₂ to 1 mol CO

Moles of CO₂ = 4.000 × 1/1

Moles of CO₂ = 4.00 mol CO₂

Option A is <em>wrong</em>.

<em>Step 3.</em> Calculate the amount of heat generated.

q = ΔH

The conversion factor is 67.6 kcal/1 mol CO₂

q = 4.00 × 67.6

q = 270 kJ

Option B is <em>wrong</em>, because it gives the heat generated by 1 mol of CO.

<em>Step 4. </em>Calculate the moles of O₂ consumed

Moles of O₂ = 2.00 mol O₂

Option C is correct.

<em>Step 5.</em> Calculate the moles of CO₂ formed

Already done in Step 2.

Moles of CO₂ = 4.00 mol CO₂

Option D is <em>wrong. </em>

<em> </em>

<em>Step 6</em>. Calculate the moles of O₂ produced

Already done in Step 4.

Moles of O₂ = 2.00 mol O₂

Option E is <em>wrong. </em>

3 0
3 years ago
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