Positron which having electric charge of +1 and spin 1/2
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Energy is absorbed by the atom.
Emission lines occur only in the case of transitions from higher to lower energy levels in which energy is emitted.
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The concentration of the chemist's working solution is 6.718 mol/L.
Given,
The volume of silver perchlorate solution (V₁) = 790 ml.
The volume of distilled water added to the silver perchlorate(V₂) = 290ml.
The concentration of a stock solution of silver perchlorate (C₂) = 18.3 mol/L.
We have to find the concentration of the chemist's working solution (C₁).
As we know,
V₁C₁ = V₂C₂
From the above formula, we get,
C₁ = V₂C₂/V₁
C₁ = 290 × 18.3/ 790
C₁ = 6.718 mol/L
The concentration of the working solution = 6.718 mol/L
Hence, the concentration of the chemist's working solution is 6.718 mol/L.
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Answer : The enthalpy change for the reaction is, 97.7 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main chemical reaction is,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :
(1)

(2)

(3)

The expression for enthalpy of main reaction will be,



Therefore, the enthalpy change for the reaction is, 97.7 kJ