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2 years ago

15

In each pair of statements, choose the example that is more reliable.

2 answers:

TEA [102]2 years ago

3 0

Answer:

"statement 2" for the first pair and "statement 1" for the second pair

Explanation:

BlessedZay2 years ago

0 0

In each pair of statements, choose the example that is more reliable.

Statement 1
The company Herbal Remedies Inc. announced today that its antiobesity skin treatment is safe and effective.

Statement 2
The US Food and Drug Administration (FDA) announced today that cancer treatment X, manufactured by Pharma Inc., is safe and effective.

Statement 1
An independent chemical analysis paid for by local residents determined that wells are contaminated with dioxin at a concentration of 3 ppb.

Statement 2
The chemical company Chemicals Inc. insists that local groundwater has not been affected adversely by a leak in its waste handling system.

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What is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration ([magenta phenolph

lilavasa [31]

Answer:

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

$pH=pKa+\log\frac{[base]}{[acid]}$

Where Ka is the dissociation constant of the acid.

pKa of phenolphthalein = 9.40

pH = 10.9

So,

$10.9=9.40+\log\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}$

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

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2 years ago

WARRIOR [948]

Answer:

no

Explanation:

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2 years ago

Sulfuric acid dissolves aluminum metal according to the following reaction:

Fiesta28 [93]

Answer:

$m_{H_2SO_4}=81.7gH_2SO_4$

$m_{H_2}=1.67gH_2$

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

$2Al (s) + 3H_2SO_4 (aq)\rightarrow Al _2(SO4)_3 (aq) + 3H_2 (g)$

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

$m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4$

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

$m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2$

Best regards.

3 0

2 years ago