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Maru [420]
3 years ago
7

What is 5x-7(x+3)+2x=-25

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

5x - 7(x + 3) + 2x =  - 25 \\ 5x - 7x - 21 + 2x =  - 25 \\   - 2x - 21 + 2x =  - 25 \\  - 21 =  - 25
Something seems wrong with the question
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Each side of a square piece of cardboard is 22 inches long. What is the piece of cardboard's perimeter?
tia_tia [17]
88 inches long would be the answer
5 0
2 years ago
benito read 14 books in 3 months, which was 35% of the number of books he had signed up to read during the school year .how many
lianna [129]
14 books in 3 months is 35%
all of books is 100%

14- 35%
x- 100%
we calculate from proportions, crosswise:
x=\frac{14*100}{35}=\frac{1400}{35}=40

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Greetings,
n00nst00p :)
7 0
3 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Every set of 3 points must be ______ because connecting them makes an imaginary flat surface or plane
nikdorinn [45]
Any set of 3 points is "coplanar".
3 0
3 years ago
Chelsea has four hours of free time on Saturday. She would like to spend no more than 2/3 of an hour on each activity. How many
Galina-37 [17]
Namely, how many times 2/3 goes into 4, well, let's just divide them then

\bf \cfrac{\stackrel{\textit{total hours}}{4}}{\stackrel{\textit{hours per activity}}{\frac{2}{3}}}\implies \cfrac{\quad \frac{4}{1}\quad }{\frac{2}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{2}\implies \cfrac{12}{2}\implies 6
4 0
3 years ago
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