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Semenov [28]
3 years ago
12

Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w

hole number
Mathematics
1 answer:
Contact [7]3 years ago
5 0
There are 5280 feet in a mile
There are 3600 seconds in an hour

to get 40 miles per hour
we multiply 40 by 5280 and divide by 3600

40 * 5280 / 3600

this gets us 58.666666...
but since they want us to round to the nearest whole number, our answer would be 59 feet per second
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0.0002077 in Scientific notation
Aloiza [94]

Answer: 2.077x10^-4

Step-by-step explanation:

7 0
3 years ago
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Find the savings plan balance after 2 years with an APR of 4% and monthly payments of $250. The balance is $ (Do not round until
alexdok [17]

Answer:

$6,506.51

Step-by-step explanation:

Recall that increasing an amount C in x% is equivalent to multiply it by (1+x/100)

As we have 4% APR, the monthly interest would be (4/12)% = 0.04/12

<u>Month 0</u> (first payment)

$250

Month 1

250 + 250 \frac{0.04}{12}= 250(\frac{12.04}{12})

<u>Month 2</u>

250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2)

<u>Month 3</u>

250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3)

<u>Month 24 (2 years)</u>

250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24})

The sum  

1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24}

is the sum of the first 24 terms of a geometric sequence with common ratio \frac{12.04}{12} which is

\frac{1-(12.04/12)^{25}}{1-(12.04/12)}=26.02603071

so, after 2 years the saving balance is

250*26.02603071 = 6,506.50767= $6,506.51 rounded to the nearest cent.

6 0
3 years ago
Eddie ended round one of a game show with 800 points. In round two, he scored -400 points
german

Answer:

400

Step-by-step explanation:

800-400=400

8 0
3 years ago
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Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
3 years ago
Find the value of x.<br> 110°<br> X + 116
LenKa [72]
Xterm correct answer is =11
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