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vivado [14]
3 years ago
9

Pleaseeee helpppp I’m struggling

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

x = 9.367

Step-by-step explanation:

we have to use the sin formula so its

Sin = opp / hypotenuse

sin 42 = x / 14 <u>Multiply 14 from both side</u>

x = 14 sin 42

x = 9.367

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Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =
Genrish500 [490]
So here is how we are going to find out what is ED. 
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5. 
Hope this answer helps. Let me know if you need more help next time!</span>
5 0
4 years ago
Read 2 more answers
A company manufactures tires at a cost of $40 each. The following are probabilities of defective tires in a given production run
asambeis [7]

Answer:

The expected cost of the company for a 3000 tires batch is $120255

Step-by-step explanation:

Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires  is 3000p.

Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are A_1,\dots, A_n events that partition the whole sample space, and we have a random variable X over the sample space, then

E(X) = p(A_1)E(X|A_1) + \dots + p(A_n)E(X|A_n).

So, in this case, we have the following

E(X) = P(p=0\%)E(X|p=0\%)+P(p=1\%)E(X|p=1\%)+P(p=2\%)E(X|p=2\%)+P(p=3\%)E(X|p=3\%) = 0.1\cdot 3000\cdot 0 + 0.3\cdot 3000\cdot 0.01+ 0.4\cdot 3000\cdot 0.02+ 0.2\cdot 3000\cdot 0.03 = 51.

Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.

Finally, note that the cost of the batch would be 40Y+45X. Then

E(40Y+45X) = 40E(Y)+45E(X) = 40\cdot 2949+45\cdot 51=120255

3 0
3 years ago
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vagabundo [1.1K]

Answer:

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4x-7

4(4)-7

16-7

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