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dezoksy [38]
3 years ago
10

15=3a answer for this question????

Mathematics
1 answer:
Paul [167]3 years ago
5 0

Answer:

a=5

Step-by-step explanation:

15=3a

1. You need to try to get the variable alone, in this case its a

2. So you divide 15 by 3

3. That will give you 5=a or a=5

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3. The following sequence shows the number of pushups Kendall did each week, starting with her first week of exercising: 6, 18,
Alona [7]

{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}

SEQUENCE: 6, 18, 54, 162

18/6 = 3

54/18 = 3

162/54 = 3

then, r (common ratio) = 3

_________________________________________

RECURSIVE RULE: r = 3

an = a(n - 1) × r       [formula]

ANSWER: an = a(n - 1) × 3

_________________________________________

ITERIATIVE RULE: r = 3, a1 = 6

an = a1 × r^(n - 1)       [formula] [ ^(n-1) is an exponent]

ANSWER: an = 6 × 3^(n - 1)

4 0
3 years ago
A box of spaghetti weighs 1 pound. Lindsay
MrRissso [65]

Answer:

yes she'll be to make another meal

Step-by-step explanation:

1 pound = 16 oz

lindsay cooked nine ounces

16 - 9

8 0
3 years ago
What is 0.000000025 written in exponent form<br><br><br><br><br> plz hurry
Evgesh-ka [11]

Answer:2.5×10^-5. (And i think u meant in Scientific Notation)

Step-by-step explanation//Give thanks(and or Brainliest) if helpful (≧▽≦)//

4 0
3 years ago
What is the following sum 3b^2
densk [106]

The given expression is 3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})

This can be simplified as :

= 3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})

We know that: \sqrt[3]{27}  = 3

Similarly we also can simplify: \sqrt[3]{b^6}  = b^2

So our expression will look like this:

= 3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})

= 9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})

=\sqrt[3]{2a}*(9b^2 + 3b^2)

=\sqrt[3]{2a}*(12b^2)

This can also be written as:

12b^2(\sqrt[3]{2a})

So the Answer is Option B


6 0
3 years ago
Read 2 more answers
Pablo Picasso’s Head of a Women, is an example of a(n) ______________.
lina2011 [118]

Answer:

Sculpture in the round.

Step-by-step explanation:

Option A, sculpture in the round, is the right answer.

This is Picasso’s initial Cubist sculpture illustrations the master made of his girlfriend Fernande Olivier in the year 1909. After the return of the couple from a tour to Spain Picasso created the bust in Paris. As in his old Cubist pictures, the frame of her sculpted head is faceted into miniature pieces. Meant to be viewed in the round, the production switches form when seen from various corners. Therefore, it is clear that Pablo Picasso’s "Head of a Women" was a sculpture in the round.

8 0
3 years ago
Read 2 more answers
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