Step-by-step explanation:
Given
Hope it will help :)
Answer:
6.9
7.-5
8.-10
Step-by-step explanation:
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Angle ABC=DEF then
Side AB=DF
Side BC=EF
and Side CA=FD
So if side ac=DF
side DF=6cm.
