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harina [27]
3 years ago
11

A linear function F models a relationship in which the dependent variable decreases 6 units for every 3 units the independent va

riable decreases. The value of the function at 0 is 4. Graph the function. Identify the slope, y-intercept, and x-intercept of the graph.

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

A. Finding the slope

The slope of the function is simply the ratio of the value of the dependent variable over the independent variable, so in this case it is:

slope = 6/ 3 = 2

 

B. Finding the y – intercept

The y – intercept is simply the value of the dependent variable when the independent variable is equal to zero, therefore:

y – intercept (b) = 4

 

C. Finding the function of the graph

The general equation of a line is given as:

y = m x + b

where m is the slope and b is the y intercept therefore:

y = 2 x + 4

 

D. Finding the x – intercept

The x – intercept is simply the value of the independent variable (x) when the dependent variable (y) is equal to zero, therefore:

0 = 2 x + 4

x = - 2

 

E. Graph the function

<span>Check out the image attached</span>

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Please Help me Check the image below!!!!!
WITCHER [35]

Answer:

First question:

The graph of  y=\frac{3-2x}{2-3x} has a vertical asymptote at x =  \frac{2}{3} and a horizontal asymptote at y =  \frac{2}{3}

Second question:

The graph of equation y=\frac{1-3x}{2+x} has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the  denominator is equal to zero

The horizontal asymptotes will occur if:

  • Both polynomials are the same degree, divide the coefficients of the highest degree terms
  • The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

∵ y=\frac{3-2x}{2-3x}

- To find the vertical asymptote equate the denominator by 0

   to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

∴ \frac{2}{3} = x

∴ The graph has a vertical asymptote at x =  \frac{2}{3}

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = \frac{2}{3}

∴ The graph has a horizontal asymptote at y =  \frac{2}{3}

The graph of  y=\frac{3-2x}{2-3x} has a vertical asymptote at x =  \frac{2}{3} and a horizontal asymptote at y =  \frac{2}{3}

Second question:

The graph has a horizontal asymptote at y = -3

<em />

<em>means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3</em>

  • In all answers the numerator and the denominator have the same highest degree
  • Lets look for the coefficients of x up and down to find which one gives quotient of -3

∵ In answer A the quotient is 1 because x up and down have

  coefficient 1

∵ In answer B the quotient is -\frac{1}{3} because the coefficient of x

   up is 1 and down is -3

∵ In answer D the quotient is -1 because the coefficient of x

   up is 3 and down is -3

∵ In answer C the quotient is -3 because the coefficient of x up

   is -3 and down is 1

∴ The graph of equation y=\frac{1-3x}{2+x} has a horizontal asymptote at y = -3

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andriy [413]
Hello! First we should note that the shape of the figure can be broken down into two rectangular prisms, so that the expression will look like:

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The inequality 1.25x + 1.00y &lt; 10.00 can be used by Jason to determine how many drinks, x, and nachos, y, he can buy for him
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Answer:

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Step-by-step explanation:

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