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DedPeter [7]
3 years ago
15

Can you explain please?

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer: To right in different numbers

Step-by-step explanation:

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An isosceles triangle in which the two equal sides, labeled x, are longer than side y.
Mrac [35]

Answer:

2.1 plus 2 x equals 7.5

Step-by-step explanation:

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3 years ago
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Write an expression to represent . Eight less than the product of two and a number x
kvv77 [185]
The answer is 2x-8 where “the product of two and a number” is the 2x and 8 less is to subtract 8 from the 2x so your answer is 2x-8
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3 years ago
Identify the property being shown here, assuming that a + 2 = y. <br> (a + 2)/3 = y/3
allochka39001 [22]

Assuming that <em>a + 2 = y</em>, the property that was applied to arrived at <em>(a + 2)/3 = y/3</em> is the: division property of equality.

<em><u>Recall:</u></em>

What is done to both sides of an equation will determine what property of equality was applied to the equation.

  • Thus, given the equation:

a + 2 = y

  • The following was obtained:

(a + 2)/3 = y/3

Observing the equation stated above, we will see that both sides of the equation was divided by three. This makes both sides equal.

Therefore, assuming that <em>a + 2 = y</em>, the property that was applied to arrived at <em>(a + 2)/3 = y/3</em> is the: division property of equality.

Learn more here:

brainly.com/question/13260378

4 0
2 years ago
A school wishes to accept 2000 students for their freshman class, and they expect 20,000 applications. In order to make their ad
vovangra [49]

Answer:

456

Step-by-step explanation:

Let X be the SATscore scored by the students

Given that X is normal (1000,200)

By converting into standard normal variate we can say that

z=\frac{x-1000}{200} is N(0,1)

To find the top 10% we consider the 90th percentile for z score

Z 90th percentile = 1.28

X= 200+1.28(200)\\= 200+256\\=456

i.e. only students who scored 456 or above only should be considered.

3 0
3 years ago
AB=√202−162=√400−256=√144=12
ruslelena [56]
.6 is the answer YAYA
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