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3 years ago

According to the partial construction shown, what is the next step in constructing a line parallel to a given line?

Mathematics

2 answers:

Fofino [41]3 years ago

4 0

Answer:

place compass at P and, with compass set to segment AB, draw an arc that intersects line PA.

Step-by-step explanation:

sp2606 [1]3 years ago

3 0

Answer:

Place compass at P and, with compass set to segment AB, draw an arc that intersects line PA ⇒ 2nd answer

Step-by-step explanation:

"I have added screenshot of the complete question as well as the

diagram"

* Lets revise how to construct a parallel line to a given line

1. Using your straightedge, draw a transversal through point P

This is simply a straight line which passes through P and intersects

with the given line

2. Using the construction COPY AN ANGLE, construct a copy of the

angle formed by the transversal and the given line such that the

vertex of the copied angle will be point P

3. Draw an arc centered at A and intersecting the given line and the

transversal at B and C.

4. Draw an arc of the same distance centered at P intersecting the

transversal at C'

5. Use the compass to measure the distance from B to C, and

with the compass centered at C' scribe an arc whose radius is

the distance from B to C intersecting the arc from Step 4 at B'.

6. Draw the line from P through B' which is the parallel line to the

given line

* Now lets solve the problem

- The next step in constructing a line parallel to a given line is

Place compass at P and, with compass set to segment AB, draw

an arc that intersects line PA.

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30 points! You start at (-2, 2). You move left 3 units and right 10 units. Where do you end?

Cerrena [4.2K]

Answer:

The answer is (5, 2)

Step-by-step explanation:

I. If move left = -x

move right = +x

So -2 - 3 = -5 => move left

-5 + 10 = 5 => move right

I suggest that move left and right is x cordinate

The answer is (5,2)

Is that correct?

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3 years ago

What is the quotient in the polynomial form?

Oxana [17]

First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.

Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.

Next step is to add this column.

Now repeat the same method again till the last colum.

At the end we have got 0 after the addition. Which means the remainder is 0.

So, the quotient is 2x^2-2x+2.

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3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Easy question please help

iris [78.8K]

Answer:

$17/ $25/$41

Step-by-step explanation:

brainliest pls

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2 years ago

Read 2 more answers

Write an equation in slope-intercept form of the line that passes through (7, 2) and (2, 12).

Gnoma [55]

Answer:

Step-by-step explanation:

(12 - 2)/(2 - 7) = 10/-5 = -2

y - 12 = -2(x - 2)

y - 12 = -2x + 2

y = -2x + 14

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3 years ago