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Kryger [21]
4 years ago
10

Gwen

Mathematics
1 answer:
Triss [41]4 years ago
4 0

Answer:

10, 11, and 7.

Step-by-step explanation:

28 items = $108

We know 7 of each item was handed out.

So we can start subtracting each item and its total cost.

First item:

7 balloons = $21

Then we have left:

21 items = $87

Next item:

7 candy = $28

Then we have left:

14 items = $59

Next item:

7 caps = $35

Then we have left:

7 items = $24

This is what we must solve. We know that one of the items ran out, so we just need to figure which two items still had more remaining.

There are only three ways you can split 7 into two different items. 1 and 6, 2 and 5, or 3 and 4.if you test each pair on the prices of the items you will see that only one possibility goes in evenly.

3($4.00 item) + 4($3.00) = $24

We can conclude that hats ran out at 7, balloons total was 11 (7+4), and candy total was 10 (7+3).

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Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

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Exponential form:
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Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
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Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
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