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3 years ago

Taylor is building a brick patio. A diagram of the patio is shown. Which is the area of Taylor's patio?

Mathematics

2 answers:

Illusion [34]3 years ago

7 0

Answer:

we need the diagram

Step-by-step explanation:

xenn [34]3 years ago

5 0

Answer:

the answer is 36

Step-by-step explanation:

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Please help me! i'm stuck on it

den301095 [7]

Answer:

x = 15.4

Step-by-step explanation:

Because this is a right triangle, you can use the pythagorean theorem to find the length of the hypotenuse. the theorem is a^2 + b^2 = c^2

9^2 + 12.5^2 = c^2

solving this will give you 15.4

8 0

3 years ago

Find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8 ,10,12 and 30.

Nookie1986 [14]

Well, that means that it is 3 more than a common multipule of 8,10,12, and 30
find the lcm

8=2*2*2
10=2*5
12=2*2*3
30=2*3*5
lcm=2*2*2*3*5=120
times it by 2 to get it between 200 and 500
240
add 3
243 is da number

5 0

3 years ago

Read 2 more answers

Please help what is q-75=50

kogti [31]

You have to add 75 to Both sides and 50+75= 125 So q=125. Hope this helped!

4 0

3 years ago

Read 2 more answers

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

What are the coordinates of point P?

Nadusha1986 [10]

Answer:

(-4,3)

Step-by-step explanation:

hope this helps :)

6 0

2 years ago