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3 years ago

Taylor is building a brick patio. A diagram of the patio is shown. Which is the area of Taylor's patio?

Mathematics

2 answers:

Illusion [34]3 years ago

7 0

Answer:

we need the diagram

Step-by-step explanation:

xenn [34]3 years ago

5 0

Answer:

the answer is 36

Step-by-step explanation:

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There are 20 beads in a bag, of which 8 beads are white, 2 beads are yellow, 6 beads are green, and the rest are blue. Janina wi

USPshnik [31]

Answer:

8/20 in simplest form this would be 2/5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Iris is a saleswoman whose base pay plus commissions amounted to

Anit [1.1K]

Answer:

Step-by-step explanation:

38% (Answer C)

Her $69,464 total pay was made up of $39,710 base pay and commissions.

Subtracting the latter figure from the former, we get $29,754, the amount of commissions Iris earned.

Determine what percentage of the $78,300 in sales is represented by this $29,754 in commissions:

$29,754

--------------- * 100% = 38% (Answer C)

$78,300

7 0

4 years ago

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

Billy started with 2 poems in his journal. Then he started writing 4 poems each day. Which of the following graph represents Bil

Mama L [17]

The equation would be y = 4x + 2 so just look with a graph that has a y-intercept of two, as well as moves up four and up 1 each time.

x / y
0 / 2
1 / 6
2/ 10
3 / 14
4 / 18
5 / 22
6 / 26
7 / 30

8 0

3 years ago

Read 2 more answers

An h = 135-ft tower is located on the side of a mountain that is inclined 32° to the horizontal. A guy wire is to be attached to

Vikentia [17]

Answer:

171 foot

Step-by-step explanation:

We are given that

Height of tower=135 ft

AC=55 ft

Let x be the length of shortest length of wire.