Question

Identify the 12th term of a geometric sequence where a1 = 8 and a6 = −8,192.

Answer 1

Answer:

−57,395,628

: )

Answer 2

Geometric sequence
$a_{n}=a_{1}*r^{n-1}$
r=common ratio
a1=first term
find r

a1=8
a6=-8192
$-8192=a_{6}=8*r^{6-1}$
$-8192=8*r^{5}$
divide both sides by 8
$-1024=8*r^{5}$
take 5th root of both sides
-4=r
sub
$a_{12}=8*(-4)^{12-1}$
$a_{12}=8*(-4)^{11}$
$a_{12}=8*-4194304$
$a_{12}=-33554432$