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MA_775_DIABLO [31]

2 years ago

9

On her way to her grandmothers house, Jackie traveled 3 times as many miles by train as by bus. She travelled 4 times as many mi

les by bus than as by foot. If Jackie travelled 34 miles in all, how many miles did she travel by train?

1 answer:

Vera_Pavlovna [14]2 years ago

3 0

Answer:

22 because it is just a train that they are talking about not how long it takes to get to grandmas house

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If a triangle has a height of 7 centimeters and a base of 4 centimeters,what is the area

sattari [20]

Answer:

14cm^2

Step-by-step explanation:

Area of a triangle is (base×height)/2

(4×7)/2

28/2

=14 centimetres squared

8 0

3 years ago

goran spent $38 on fruit at the grocey store.He spent a total of 40$ at the store.what percentage of the total he spend of the f

lakkis [162]

The answer should be 95% I hope this helps :)

5 0

2 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

2 years ago

Svetach [21]

I = $ 1,200,000.00

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 3%/100 = 0.03 per year,

then, solving our equation

I = 1000000 × 0.03 × 40 = 1200000

I = $ 1,200,000.00

The simple interest accumulated

on a principal of $ 1,000,000.00

at a rate of 3% per year

for 40 years is $ 1,200,000.00.

3 0

2 years ago

Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).

fiasKO [112]

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

$y = 6(7x + 9)(8x - 3)$

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

$7x + 9 = 0$

$7x = -9$

$x = -\frac{9}{7}$

So (-9/7, 0) is a zero of the quadratic function.

The other is:

$8x - 3 = 0$

$8x = 3$

$x = \frac{3}{8}$

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

6 0

2 years ago