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2 years ago

Which of the following is an advantage to co-evolving with a pollinator, rather than using wind pollination?

Biology

1 answer:

tiny-mole [99]2 years ago

4 0

Answer:

d. Pollinators rely on the flowers for food and have to pollinate to survive

Explanation:

Insect pollination is more successful as compared to wind pollination which is completely a chance event. Insect pollinated plants have evolved several strategies to attract pollinators.

The co-evolution of insect-pollinated plants further ensures the mutualism between them. Pollinators derive their food from the flowers they visit in the form of nectar.

Due to their food requirements, insects visit the flowers and in turn pollinate them. If insects do not visit the flowers, they will face the food scarcity. To ensure food availability, insects visit the flowers and pollinate them.

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Heat _____. A. is a measure of energy B.cannot move through a vacuum C. is the internal energy of matter D. is the same as tempe

Misha Larkins [42]

Answer: A. is a measure of energy

Explanation:

Heat is one of the easiest forms of energy that man can detect in your environment because we have the sensation of cold, hot, sweat, drink liquids when we feel hot, see the engine of a car heat up, take a bath of water heated by an electric shower or a boiler, etc.

Heat transfer occurs until the moment bodies reach the same temperature (thermal equilibrium). Heat is the energy transferred between a system and its surroundings because of the differences in temperatures.

7 0

3 years ago

Read 2 more answers

Which one of the following statements is true of enzyme catalysts? A) Their catalytic activity is independent of pH. B) They are

muminat

Answer:

D) They can increase the reaction rate for a given reaction by a thousand-fold or more.

Explanation:

Enzymes are like catalysts with the only difference that they are bio-molecules. Biochemical/chemical reactions are slow because of 'transition state barriers' which require a lot of energy to overcome so enzymes rather than overcoming transition state barrier provide an alternate pathway for biochemical reactions which require comparatively less energy. Thus presence of an enzyme leads to an increase in reaction rate because alternate pathway which requires less energy makes the rate of chemical reaction rapid by a thousand-fold or more.

5 0

3 years ago

10 pc

ra1l [238]

Answer:

Students who take a PE class and who will be eating sugary snacks before PE.

Explanation:

The control variable (or control group) is an experimental element which is constant or unchanged throughout the course of the experiment.

The option "students who take PE class and who will be eating sugary snacks before PE" will remain unchanged and constant because the whole point of the experiment is to see the effects on students performance in PE after eating sugary snacks.

Hope this helps :)

7 0

3 years ago

In humans, the allele for wet earwax, W, is dominant over the allele for dry earwax, w. If a man with wet earwax and a woman wit

Nonamiya [84]

It is a half and half chance, we just were learning about this! The one parent has wet and the other dry it would be half and half.

8 0

2 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago