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3 years ago

Which of the following is NOT a condition necessary for fossilization to occur?

Biology

2 answers:

Komok [63]3 years ago

4 0

Answer: E

Explanation:

Ann [662]3 years ago

3 0

Answer: B. Presence of heat

Explanation:

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Hunt and her team designed an experiment to test her hypothesis about the effect of BPA on mice. They administered daily doses o

katovenus [111]

Answer and Explanation: The figure below shows the doses of BPA administered to the female mice over time.

An experiment is used to determine cause and effect among variables. When the research is for the impact of a treatment, researchers randomly separate individuals in two groups:

Control Group doesn't receive any treament or a placebo or a treatment whose outcome is already known;
Treatment Group receives the treatment;

For the female mice on the image below, in the First Group is not injected any dosage of BPA, so they are the control group, while the others are treatment group.

The variables in a experiment are classified as independents or dependents:

Independent Variable is the cause;
Dependent Variable is the effect;

For the BPA research, since it is the effect of BPA over time on the mice's cells it is being investigated, dosage of BPA is the independent variable and time is the dependent variable.

6 0

3 years ago

Which of the following monomers are correctly matched with their polymers

Marat540 [252]

I think it's A....hope that helps at least

7 0

3 years ago

Read 2 more answers

Was perestroika successful?

allsm [11]

Answer:

Nope, it dissolved before reaching the final stages.

I hope that helps :D

6 0

3 years ago

Read 2 more answers

List the 3 components of the hand

coldgirl [10]

Carpet, meta carpel and phalanges

4 0

3 years ago

In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene

NikAS [45]

Answer:

A) 9:3:3:1

B) All bitter fruit, yellow spotted offsprings

C) Phenotypes are bitter yellow spotted (4), bitter no spot (4), sweet yellow spot (4), and sweet no spot (4). 1:1:1:1

Explanation:

This is a typical dihybrid cross involving two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

Hence, a heterozygous F1 resulting from a cross between an homozygous dominant (bitter fruit, yellow spot) and homozygous recessive (sweet fruit, no spot) will have a BbSs genotype. The heterozygous F1 offsprings are self-crossed and produce gametes BS, Bs, bS, bs. (See punnet square). The F2 offsprings will have the following phenotypes: Bitter fruit, yellow spot (9)

Bitter fruit, no spot (3)

Sweet fruit, yellow spot (3)

Sweet fruit, no spot (1)

Back cross between a F1 offspring (BbSs) and homozygous dominant parent (BBSS) will produce all bitter fruit, yellow spot offsprings (see attached image). BBSS (4), BBSs (4), BbSS (4), and BbSs (4) are the offsprings' genotypes.

For the back cross between a F1 offspring (BbSs) and a homozygous recessive (bbss) parent, the Phenotypes with their proportions are as follows:

Bitter fruit, yellow spot (BbSs, 4)

Bitter fruit, no spot (Bbss, 4)

Sweet fruit, yellow spot (bbSs, 4)

Sweet fruit, no spot (bbss, 4).

4 0

3 years ago