One side of a triangle is twice as long as a second side. The third
1 answer:
Answer:
The longest possible values of the other two sides are 7 ft and 14 ft
Step-by-step explanation:
Let one side of the triangle be x and the other, 2x
Perimeter of a triangle = sum of all sides; i.e x+2x+33
Therefore, x+2x+12=33
Solve for x;
3x=33-12
3x=21
Divide both sides by 3; x=21/3
therefore, x=7 and
2x= (2*7) = 14
The longest possible values of the other two sides are 7 ft and 14 ft
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The correct answer would be 2y^5
No nodcause it has to me in y=mx+b form. so just sub. 1 from each side
Answer:
2/(x-3) = 4. 4x-12 = 2. x=7/2. G) 7/(2x+5) = 2/3. 21 = 4x + 10. x = 21/4. H) 7/(x-9) = 5. 7 = 5x-45. x = 52/5
Step-by-step explanation:
The decimal would be 0 because it doesn't have anything to give.
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