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3 years ago

Find the prime factorization of 36

Mathematics

2 answers:

Ghella [55]3 years ago

8 0

The prime factors of 36 are 2*2*3*3 I think. I showed a picture of my work.

Dmitrij [34]3 years ago

7 0

prime factoring, oddly enough, is simply dividing by primes, anyhow, without much adieu.

36 = 2 * 2 * 3 * 3.

but anyway, prime factoring, is dividing by first 2, till you can't, then 3 till you can't, then 5 till you can't, and so on, and that plucks out all possible factors on any number.

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Hey! I would appreciate some help with this

arsen [322]

Answer:

...

Step-by-step explanation:

since they give us the side opposite of the given angle(Opposite) and we are trying to find for a (Adjacent/side), so we use TOA

tan(30)= $\frac{4}{a}$

i see u dont want it solved but ill solve it anyways

since a is on the bottom then lets switch them

$x=\frac{4}{tan30}$

x= 6.928

4 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

4 years ago

Can square root of 27 be simplified

Studentka2010 [4]

Yes, square root of 27 can be simplified

$\sqrt{27}= \sqrt{9*3}=3 \sqrt{3}$

8 0

4 years ago

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B is the midpoint of AC. AB = 2x+12 and BC = 5x + 10. Find AC

3241004551 [841]

Answer:

x=6

Step-by-step explanation:

/AB/=2x+12

/BC/=5x+10

3x+2=5x-10 subtract 2 from both sides

3x=5x-12 subtract 5x from both sides

-2x=-12 divide both sides by -2x

x =6

5 0

2 years ago

The diameter of a circle is 4 kilometers. What is the circle's circumference?

scZoUnD [109]

Answer:

12.57 km

Step-by-step explanation:

Radius = 4 / 2 = 2 km

Circumference = 2πr = 2π(2) = 4π = 12.57 km

6 0

3 years ago

Read 2 more answers