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iren [92.7K]
2 years ago
9

Lena took a nap . she fell asleep at 11:37a.m and she woke up at 1:24p.m. how long did she sleep?

Mathematics
1 answer:
zalisa [80]2 years ago
6 0
1 hour and 57 minutes
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Write the equation in slope-intercept form. y - 2 = 6 (x + 1)​
zhannawk [14.2K]

Answer:

y=6x+8

Step-by-step explanation:

Write in slope-intercept form, y=mx+b.

7 0
3 years ago
Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for .
sp2606 [1]

Answer:

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3}  } ( \rm \: nearest \: tenth  )

Step-by-step explanation:

Given:

  • radius = 7 metres
  • height = 2 metres
  • π = 3.14

To Find:

  • Volume of the cylinder

Solution:

Use the formulae of the volume of cylinder:

\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}

where,

  • π = 3.14
  • r = radius
  • h = height

According to the question:

  • radius = 7 metres
  • height = 2 metres

Substitute the values onto the formulae in order to find out the volume:

\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2} (2)

\rm \: Volume_{(Cylinder)} = \pi(49)(2)

\rm \: Volume_{(Cylinder)} = 98\pi

\rm \: Volume_{(Cylinder)} =  \: 98 \times 3.14

\rm \: Volume_{(Cylinder)} = 307.72  \: m {}^{3} \: (exact \: form)

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3} } \: ( \rm nearest \: tenth  )

<u>Hence,we can conclude that:</u>

The volume of the cylinder is approximately

307.7m³.

8 0
1 year ago
What is the value of x? Show work.
ella [17]

Answer:

x=5

Step-by-step explanation:

This is because the inscribed angle of the circle or angle EFG is equal to the twice of the degree of the arc EG. Therefore, we can create this equation:

12+40=2(8x+10)

12+40=16x+20

20=4x

x=5

5 0
3 years ago
The end of a hose was resting on the ground, pointing up an angle. Sal measured the path of the water coming out of the hose and
Travka [436]

Answer:

3.2 feet


Step-by-step explanation:

The equation  f(x)=-0.3x^{2}+2x  shows the height of water [f(x)] and horizontal distance [x].

<em>Given the </em><em>horizontal distance is 4 feet</em><em>, they want to know the height.</em>


<em>Simply put 4 in x of the equation and solve for f(x). So,</em>

<em>f(x)=-0.3(4)^{2}+2(4)\\f(x)=3.2</em>

So, the height of the water was 3.2 feet above the ground.

4 0
2 years ago
Read 2 more answers
Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx
Soloha48 [4]

Answer:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

Step-by-step explanation:

For this case we need to find the following integral:

\int x(8-x)^{3/2}dx

And for this case we can use the substitution u = 8-x from here we see that du = -dx, and if we solve for x we got x = 8-u, so then we can rewrite the integral like this:

\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)

And if we distribute the exponents we have this:

\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du

Now we can do the integrals one by one:

\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C

And reordering the terms we have"

\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C

And rewriting in terms of x we got:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

And that would be our final answer.

8 0
2 years ago
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