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CaHeK987 [17]
3 years ago
6

Find the solution set:

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0

Answer:

Step-by-step explanation:

9x²+4x-5=0

9x²+9x-5x-5=0

9x(x+1)-5(x+1)=0

(x+1)(9x-5)=0

x=-1,5/9

vazorg [7]3 years ago
5 0

Answer:

x = - 1, x = \frac{5}{9}

Step-by-step explanation:

Given

9x² + 4x - 5 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 9 × - 5 = - 45 and sum = + 4

the factors are + 9 and - 5

Use these factors to split the x- term

9x² + 9x - 5x - 5 = 0 ( factor the first/second and third/fourth terms )

9x(x + 1) - 5(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(9x - 5) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

9x - 5 = 0 ⇒ 9x = 5 ⇒ x = \frac{5}{9}

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Lamonte has 50 m of fencing to build a three-sided fence around a rectangular plot of land that sits on a riverbank. (The fourth
MatroZZZ [7]

The dimensions of the rectangular plot of land that sits on a riverbank is 32 m by 9 m or 18 m by 16 m.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

Let x represent the length and y represent the width. Hence:

x + 2y = 50

x = 50 - 2y

Also:

xy = 288

(50 - 2y)y = 288

y = 9; and y = 16

x = 32; and x = 18

The dimensions of the rectangular plot of land that sits on a riverbank is 32 m by 9 m or 18 m by 16 m.

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6 0
1 year ago
Find the equation of a line that passes through (2,8) and is parallel to the graph of y=2x+6. Write the equation in slope-interc
Rashid [163]

Answer:

The equation of a parallel line would be y = 2x + 4

Step-by-step explanation:

In order to find the equation of this line, we first have to note that paralell lines have same slopes. Therefore, since the original line has a slope of 2, we know the new line will have a slope of 2. Now we can use that information along with the given point in point-slope form to find the equation.

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3 0
2 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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