If the first roll is a three, then the only chance of the sum of the two numbers being less than six is if you roll a 1 or a 2.
That is 2/6 chance, or simplified, a 1/3 chance.
I hope this Helps!
Answer:
2 x (3 y^3 + 2)
Step-by-step explanation:
Simplify the following:
2 x + x + x + 2×3 y y x y
2 y×3 y = 2 y^2×3:
2 x + x + x + 2×3 y^2 x y
2×3 = 6:
2 x + x + x + 6 y^2 x y
6 y^2 x y = 6 y^(2 + 1) x:
2 x + x + x + 6 y^(2 + 1) x
2 + 1 = 3:
2 x + x + x + 6 y^3 x
Grouping like terms, 2 x + x + x + 6 y^3 x = 6 x y^3 + (2 x + x + x):
6 x y^3 + (2 x + x + x)
2 x + x + x = 4 x:
6 x y^3 + 4 x
Factor 2 x out of 6 x y^3 + 4 x:
Answer: 2 x (3 y^3 + 2)
Answer:
y=1/7x
Step-by-step explanation:
Answer:
Probability of obtaining 6H and 4T = 0.2051
Step-by-step explanation:
Since for a fair coin,
Probability of obtaining Head = 0.5
p = 0.5
q = 1-p = 0.5
Probability of obtaining 6H and 4T = 10C6 (p)^6(q)^4 = 210*0.5^6*0.5^4
P(6H, 4T) = 0.2051
Answer:
m= 1/3
Step-by-step explanation:
m = 
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