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liubo4ka [24]
2 years ago
7

Given the data set (200, 150, 325, 350, 100, 75), Find the range of the data set

Mathematics
1 answer:
andriy [413]2 years ago
4 0
The range is just the distance between the biggest number
and the smallest one.

The biggest number on that list is  350 .
The smallest number on that list is  75 .

The range is from  75 to 350, or a distance of  275 .
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If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
2 years ago
Need help please I don’t understand this question
Salsk061 [2.6K]

Answer:

a) 9

Step-by-step explanation:

f(2) basically equals to y when x=2 and the y coordinate at x=2 is 9

5 0
3 years ago
Andre and Morgan are both headed to Florida for vacation. Andre will drive 70 miles per hour. Morgan will drive 55 miles per hou
babymother [125]

Answer:

The number of hours Moran wold have driven before Andre catches up with him is 14 hours

Step-by-step explanation:

The given information are;

The speed with which Andre will drive = 70 miles per hour

The speed with which Morgan will drive = 55 miles per hour

The time of departure of Morgan = 3 hours before Andre departs

Let the time at which Andre catches up with Morgan be, t

We have, from the definition of distance traveled;

Distance traveled =Speed × Time

The distance Morgan would have driven in t hours = 55 × t

Given that to catch up with Morgan, Andre has to travel the same distance, and that Andre starts 3 hours late, we have;

The distance Andre would  drive when Morgan has driven for t hours = 70 × (t - 3)

Therefore, since the distance at the point they meet is the same distance for them both, we have;

55 × t = 70 × (t - 3)

55 × t = 70 × t - 210

210 = 70 × t - 55 × t  = 15 × t

t = 210/15 = 14 hours

Therefore, Morgan would have driven for 14 hours before Andre catches uo with him.

4 0
3 years ago
Pls answer if u know :) <br><br> This is a very important homework and i was gone for days so idk
aliya0001 [1]

Answer:

Option B

Step-by-step explanation:

Slope of the line is calculated by the formula:

m=\frac{y_2-y_1}{x_2-x_1}\\\\

We have the points ( -2 , 4) and (3 , -5) so plug in the values in the formula:

m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{-5-4}{3-(-2)}\\\\m=\frac{-9}{5}\\

so the slope(m) equals -9/5

6 0
3 years ago
Charlotte and Edgar's ages add up to 22. Charlotte is one year
nadya68 [22]

Answer: Charlotte's 15 and Edgar's 7

Step-by-step explanation:

7*2=14

14+1 = 15

15 + 7 = 22

8 0
2 years ago
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