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Irina-Kira [14]
3 years ago
9

1. Solve the quantity x minus 5, end quantity, over x, minus 1, equals the quantity x plus 3, end quantity, over x.

Mathematics
1 answer:
meriva3 years ago
8 0
1.
( x - 5 ) / x   -  1 = ( x + 3 ) / x    / · x ( we will multiply both sides by x )
x - 5 - x = x + 3
- x = 3 + 8
- x = 8
x = - 8
Answer: D ) 8
2.
2/(8 x²) = 1/ 8 x   / · x
2 / 8 x = 1 / 8
8 x = 16
x = 16 : 8
x = 2
Answer: D ) 2
3.
( x + 4 )/ x  + 1 = ( x + 6 ) / x              / · x
x + 4 + x = x + 6
x = 6 - 4
x = 2
Answer: B ) 2
4. 
1 / 6 = 3 / ( x + 12 )
x + 12 = 18
x = 18 - 12
x = 6
Answer: A ) 6
       
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Simplify 4x + 8 + 2x − 7.
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Answer:

6x+1

Step-by-step explanation:

1. Add the x

4x+2x=6x

2. Add the numbers

8-7=1

3. Add everything

6x+1

Hope this helps!

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3 years ago
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I'm doing integers one step equations what is s-1=10
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Get the variable alone, so add the one to both sides.
s=10+1.
Next simplify.
s=11.
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Match each expression on the left with an equivalent expression on the right
Lana71 [14]
Answer: See explanation
Step-by-step explanation:
You didn't give the expressions but here are some expressions
a. ✓4x²y^4. 1. 2x✓y
b. ✓8x²y. 2. 2y✓2x
c. ✓4x²y. 3. 2xy²
d. ✓16xy². 4. 2x✓2y
e. ✓8xy². 5. 4y✓x
a. ✓4x²y^4 = ✓4 × ✓x² × ✓y^4
= 2 × x × y²
= 2xy²
Therefore, ✓4x²y^4 = 2xy²
b. ✓8x²y = ✓8 × ✓x² × ✓y
= ✓4 × ✓2 × ✓x² × ✓y
= 2 × ✓2 × x × ✓y
= 2x✓2y
Therefore, ✓8x²y = 2x✓2y
c. ✓4x²y = ✓4 × ✓x² × ✓y
= 2 × x × ✓y
= 2x✓y
Therefore, ✓4x²y = 2x✓y
d. ✓16xy² = ✓16 × ✓x × ✓y²
= 4 × ✓x × y
= 4y✓x
Therefore, ✓16xy² = 4y✓x
e. ✓8xy² = ✓8 × ✓x × ✓y²
= ✓4 × ✓2 × ✓x × ✓y²
8 0
3 years ago
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How do I find two consecutive integers whose sum is 234
Verizon [17]
Divide 234 by 2
=117
Then just add and subtract one.
116 and 118 is the answer ( both numbers )
5 0
4 years ago
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