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Irina-Kira [14]
3 years ago
9

1. Solve the quantity x minus 5, end quantity, over x, minus 1, equals the quantity x plus 3, end quantity, over x.

Mathematics
1 answer:
meriva3 years ago
8 0
1.
( x - 5 ) / x   -  1 = ( x + 3 ) / x    / · x ( we will multiply both sides by x )
x - 5 - x = x + 3
- x = 3 + 8
- x = 8
x = - 8
Answer: D ) 8
2.
2/(8 x²) = 1/ 8 x   / · x
2 / 8 x = 1 / 8
8 x = 16
x = 16 : 8
x = 2
Answer: D ) 2
3.
( x + 4 )/ x  + 1 = ( x + 6 ) / x              / · x
x + 4 + x = x + 6
x = 6 - 4
x = 2
Answer: B ) 2
4. 
1 / 6 = 3 / ( x + 12 )
x + 12 = 18
x = 18 - 12
x = 6
Answer: A ) 6
       
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They have equal slopes.

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4 years ago
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An architect in Brussels measures something to be 2.5 feet (using the Brussels measurement). How many feet is this in Aalst (usi
borishaifa [10]

Answer:

2.487F

Step-by-step explanation:

From the question we are told that

Architect Measures 2.5 feet (using the Brussels measurement)

Generally in Brussels  1F=275.75mm

Therefore

    2.5F=689.375mm

Generally in Aalst 1F=277.2mm

Therefore Mathematically converting  to feet in Aalst measurement we get

    689.375mm*\frac{1}{277.2} =2.487F

   

6 0
3 years ago
A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x. Find the height of t
weqwewe [10]
V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y

V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h

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7 0
4 years ago
If i earn $8.10 and hour and worked 6 hours a day how many days would i need to work to get 470 hours.
prisoha [69]
Since 470/6 = 78.333 it would take you 78.333 days to work 470 hours.
4 0
3 years ago
Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s
r-ruslan [8.4K]

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
4 years ago
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