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Studentka2010 [4]

3 years ago

14

Finn bought 2 packs of stickers. A friend gave him 4 more stickers. Now he has 24 stickers in all. How many stickers were in eac

h pack.

2 answers:

Murljashka [212]3 years ago

6 0

2x+4=24 -4 -4 ------------- 2x=20 ÷2 ÷2 ---------- X=10 So 10 stickers in each pack

vladimir2022 [97]3 years ago

3 0

2 packs of stickers.
4 more stickers.
24 stickers in total.

24 - 4 = 20
20 ÷ 2 = 10
10 stickers per pack.

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The fish tank has side lengths 20in, 10in and height 15in. The water level is two inches below the top of the tank. A glass sphe

Kitty [74]

Answer:

Part 1) The new distance from the water to the top of the tank is $1.979\ in$

Part 2) The maximum number of balls that can be put into the tank with the tank not overflowing is 95

Step-by-step explanation:

step 1

Find the total volume of the tank

$V=20*10*15=3,000\ in^{3}$

step 2

Find the volume of the tank if the water level is two inches below the top of the tank

$V=20*10*(15-2)=2,600\ in^{3}$

step 3

Find the volume of the glass sphere

The volume of the glass sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=1\ in$

assume

$\pi=3.14$

substitute

$V=\frac{4}{3}(3.14)(1)^{3}$

$V=4.2\ in^{3}$

step 4

What is the new distance from the water to the top of the tank?

we know that

$2 in -----> represent (3,000-2,600)=400\ in^{3}$

so

using proportion

Find how many inches correspond a volume of $4.2\ in^{3}$

$\frac{2}{400}\frac{in}{in^{3}}=\frac{x}{4.2}\frac{in}{in^{3}}\\ \\x=4.2*2/400\\ \\x=0.021\ in$

The new distance from the water to the top of the tank is

$2-0.021=1.979\ in$

step 5

Find how many of these balls can be put into the tank with the tank not overflowing

we know that

The volume of one ball is equal to $4.2\ in^{3}$

using proportion

$\frac{1}{4.2}=\frac{x}{400}\\ \\x=400/4.2\\ \\x=95.23\ balls$

therefore

The maximum number of balls that can be put into the tank with the tank not overflowing is 95

4 0

3 years ago

If y= 2x-3 were chnged to y=2x+5 how would the graph of the new function compare with the original

ivanzaharov [21]

The new function moved up by 8 units from the original.

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See the attached image for a graph of both functions. The new function is the solid blue line.

8 0

2 years ago

Read 2 more answers

Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for

skad [1K]

m = 90 - 6d is the equation to determine m, the number of measures Harita still needs to memorize, as a function of d, the number of days of practice since she began learning the piece

<em><u>Solution:</u></em>

Given that Harita must memorize 90 measures of music for her cello solo at a concert

To find: equation to determine m, the number of measures Harita still needs to memorize, as a function of d, the number of days of practice since she began learning the piece

Let "m" be the number of measures Harita still needs to memorize

Let "d" be the number of days of practice since she began learning the piece

Given that She plans on memorizing 18 new measures for every 3 days of practice

<em><u>Rate per day is given as:</u></em>

$\frac{18}{3} = 6$

Therefore she memorises 6 per day

<em><u>Therefore, the equation that relates 'm' to 'd' is: </u></em>

m = total measures of music she must memorise - (number of measures she memorises per day x d)

m = 90 - 6(d)

m = 90 - 6d

Thus the required equation is found

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3 years ago

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Effectus [21]

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3 years ago

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Rufina [12.5K]

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3 years ago