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forsale [732]
3 years ago
9

Help me with this problem please

Mathematics
2 answers:
labwork [276]3 years ago
6 0

Answer:

-15

Step-by-step explanation:

Order of Operations: BPEMDAS

1. Brackets

2. Parenthesis

3. Exponents

4. Multiplication

5. Division

6. Addition

7. Subtraction

Left to Right

Step 1: Write expression

3² - 3 · [(5² - 9) ÷ 2]

Step 2: Brackets Parenthesis Exponents

3² - 3 · [(25 - 9) ÷ 2]

Step 3: Brackets Parenthesis Subtraction

3² - 3 · [16 ÷ 2]

Step 4: Brackets Division

3² - 3 · 8

Step 5: Exponents

9 - 3 · 8

Step 6: Multiplication

9 - 24

Step 7: Subtraction

-15

Ymorist [56]3 years ago
5 0

Answer:

-15

Step-by-step explanation:

3^2 - 3 x [(5^2 - 9) / 2 ]

9 - 3 x [(25 - 9) / 2]

9 - 3 x (16/2)

9 - 3 x 8

9 - 24

-15

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The square root of 162 in its simplest form means to get the number 162 inside the radical √ as low as possible.

Here is how to do that! First we write the square root of 162 like this:

√162

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√81 × 2

Next, we separate the numbers inside the √ as such:

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Step-by-step explanation:

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300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
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