ANSWER
![x = 13](https://tex.z-dn.net/?f=x%20%3D%2013)
EXPLANATION
Use the Pythagoras Theorem to obtain,
![{x}^{2} = {12}^{2} + {5}^{2}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%20%7B12%7D%5E%7B2%7D%20%20%2B%20%20%7B5%7D%5E%7B2%7D%20)
This implies that,
![{x}^{2} = 144 + 25](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20144%20%2B%2025)
![{x}^{2} = 169](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20169)
Take the positive square root of both sides to get,
![x = \sqrt{169}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%7B169%7D%20)
![x = 13](https://tex.z-dn.net/?f=x%20%3D%2013)
Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one
If this question is about percent whole and part then the answer is
Answer:
a
Step-by-step explanation:
i am the smort
\