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mel-nik [20]
3 years ago
7

Clara solved the equation 7 3 x = − 2 3 as shown. 7 3 x ( 3 7 ) = − 2 3 ( 3 7 ) x = −14 What is Clara’s error? Clara should have

divided by StartFraction 3 over 7 EndFraction. Clara should have added StartFraction 7 over 3 EndFraction. Clara should have multiplied by StartFraction 7 over 3 EndFraction. The solution is Negative StartFraction 2 over 7 EndFraction, not –14.
Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0
Answer:15 hope this helps
hjlf3 years ago
4 0

Answer:

15

Step-by-step explanation:

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Among 10 laptop computers, five are good and five have defects. Unaware of this, a customer buys 6 laptops.What is the probabili
cupoosta [38]
1:3
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3 0
3 years ago
Simplify the following radical
Gelneren [198K]

Answer:

\large\boxed{2\sqrt[5]{64x^6y}=4x\sqrt[5]{2xy}}

Step-by-step explanation:

\text{Use}\\\sqrt[n]{a^n}=a\\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\a^n\cdot a^m=a^{nm}\\----------------\\\\2\sqrt[5]{64x^6y}=2\sqrt[5]{64}\cdot\sqrt[5]{x^6}\cdot\sqrt[5]{y}=(*)\\\\\sqrt[5]{64}=\sqrt[5]{32\cdot2}=\sqrt[5]{32}\cdot\sqrt[5]2=\sqrt[5]{2^5}\cdot\sqrt[5]2=2\sqrt[5]2\\\sqrt[5]{x^6}=\sqrt[5]{x^{5+1}}=\sqrt[5]{x^5\cdot x^1}=\sqrt[5]{x^5}\cdot\sqrt[5]{x}=x\sqrt[5]{x}\\\\(*)=2\cdot2\sqrt[5]2\cdot x\sqrt[5]{x}\cdot\sqrt[5]{y}=4x\sqrt[5]{2xy}

7 0
3 years ago
What is -S to the power of three minus 5st, S= -3 and T= -2.
Westkost [7]
=-3 to the power 3 - 5(-3(-2)
=-27-5(6)
=-27-30
=-57
5 0
3 years ago
Write a function using function notation to describe each situation. Find a reasonably domain and range for each function. A new
uysha [10]

Answer:

The answer is below

Step-by-step explanation:

The domain of a function is the set of all independent variables for the function while the range of a function is the set of all possible dependent variables.

Let x represent the number of newspaper lines and f(x) be the charges for advertisement. x is the independent variable and f(x) is the dependent variable.

Since the newspaper charges $3 per line for the first 4 lines plus a $20 fee to advertise, the function is given as:

f(x) = 3x + 20 for 0 < x < 4

But for more than four lines, the charges is given as:

f(x) = 12 + 20 = 32         4 < x < ∞

Therefore, the domain and range of the function is:

Domain = (0, ∞)

Range = (20, 32}

8 0
3 years ago
How to calculate this limit?
Dahasolnce [82]
Use an advanced calc
3 0
3 years ago
Read 2 more answers
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