Answer:4 and 3x-2 are roots of 12x-8.
Step-by-step explanation: Expression contains no equality sign
<span>(5x-6)(5x+6)
= (5x)^2 - 6^2
= 25x^2 - 36</span>
Answer:
Answers below.
Step-by-step explanation:
Inititally as x increases, y remains the same.
Afterword, the slope = 2 for x = 3 to x = 5.
the slope = 1 for x =5 to x =9.
the greatest value of y is y = 4 when x = 5.
Let's factorise it :

![\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }](https://tex.z-dn.net/?f=%5C%3A%20%7B%5Cqquad%20%20%5Cdashrightarrow%20%5Csf%20%20%20%20%7Bx%7D%5E%7B3%7D%20%28x%20%2B%203%29%20%2B%20%5B-5%28x%20%2B%203%29%5D%20%20%7D)
Using Distributive property we get :



⠀
Therefore,

Answer:
The zeros are:

- The function has three distinct real zeros.
Hence, option (B) is true.
Step-by-step explanation:
Given the expression

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

switch sides

as

so

Using the zero factor principle
so


Thus, the zeros are:

It is clear that there are three zeros and all the zeros are distinct real numbers.
Therefore,
- The function has three distinct real zeros.
Hence, option (B) is true.