All categories

3 years ago

Identify the figure that illustrates "A reflection in line k."

Mathematics

2 answers:

dlinn [17]3 years ago

8 0

The 1st figure is correct, the 4th one seems very similar to the 1st one. But the red shape is closer to line k. So the 1st one is correct

Lelu [443]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

PQ=2x+1 and QR=5x-44; Find PR

Dima020 [189]

Answer:

x=15

Step-by-step explanation:

subtract 1 from both sides so you are left with 2x=5x-45

then subtract 5x from both sides and you have -3x=-45

then finally divide -3 from -45 to get x=15

4 0

3 years ago

so i just failed a test which somehow brought my grade from a b+ to a d how is that possible guys?!!!! im screwed and dead

mixer [17]

Answer:

Your previous grades must have been really high and messed up your average once you failed, bringing your grade down a lot.

Step-by-step explanation:

6 0

3 years ago

Find the perimeter of the square. (hint : make one side = to the other side to find y. Remember, you are finding the perimeter)

Anestetic [448]

Step-by-step explanation:

$5y = 4y + 3 \\ y = 3 \\ p = 4 \times a = 4 \times 3 = 12$

7 0

3 years ago

David goes into a candy store with $5.00. he buys 9 peppermints for $0.15 each, and some sour candies. each sour candy costs $0.

ANEK [815]

Step one. $5.00 - 9 peppermints
= $5.00 - $1.35
= $3.65
Step two. Figure out how many 25 cents are in $3.65.
$3.65 divided by .25
= 14.6 So David can buy 14 sour candies.

7 0

3 years ago

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

4 years ago