Answer:
( f h ) (x) = 6 x² - 1
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given<em> f(x) = 3 x - 4</em>
g (x) = −x²+2 x−5
<em> h (x) = 2 x² + 1</em>
j (x) = 6 x + 2 - 8 x
K (x) = 3 x² - x + 7
<u><em>Step(ii)</em></u>:-
<em>( f h ) (x) = f ( h (x)) = f ( 2 x² + 1 )</em>
= 3 (2 x² + 1 ) - 4
= 3 ((2 x² ) + 3 - 4
= <em>6 x² - 1</em>
<u><em> Final answer:</em></u>-
∴ <em> ( f h ) (x) = 6 x² - 1</em>
B) No, set of side lengths does not satisfy Triangle Inequality Theorem
Answer:
Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.
Amplitude: 1
Period: π
Phase Shift: 0 (
0 to the right)
Vertical Shift: 1
Answer:
12, 17, 24
Step-by-step explanation:
To find the first 3 terms, substitute n = 1, 2, 3 into the rule, that is
T₁ = 1² + 2(1) + 9 = 1 + 2 + 9 = 12
T₂ = 2² + 2(2) + 9 = 4 + 4 + 9 = 17
T₃ = 3² + 2(3) + 9 = 9 + 6 + 9 = 24
