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kherson [118]
3 years ago
14

Trey solved the equation 1/4(8x+16) = 4x, the answer he got was 8=x. Describe the error he made. Then solve the problem...PLZ HE

LP!!!
Mathematics
2 answers:
Dimas [21]3 years ago
8 0
In this case, you can multiply both sides by 4 to get rid of the 1/4 real quick.
4[1/4(8x+16=4x]
8x+16=16x
8x=16
x=2
tamaranim1 [39]3 years ago
8 0

Answer:

×=2 and where are the steps to show his error?

Step-by-step explanation:

1.Distribute the 1/4.

2. 2x+4=4x-2x.

subtract 2x.

3.4=4x-2x

4. Add like terms

5.4=2x

6.Divide 2

2=x

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Vitek1552 [10]
First you subtract 6 from both sides to get:
      4h=24
Then divide by 4:
      h=6
With these problems, use the steps of either
PEDMAS, or <em></em>Please Excuse My Dear Aunt Sally.

the P stands for Parenthesis, the E for exponents, the M for multiplication, the D for division, the A for addition, and the S for subtraction


6 0
3 years ago
Read 2 more answers
The first term of an arithmetic sequence is –12 and the ninth
shtirl [24]

Answer:

d = \frac{7}{2}

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₉ = 16 , then

- 12 + 8d = 16 ( add 12 to both sides )

8d = 28 ( divide both sides by 8 )

d = \frac{28}{8} = \frac{7}{2}

8 0
3 years ago
How do I do this help
tatuchka [14]
6÷40.5= $6.75 per hour
8÷54= $6.75 per hour
y= 6.75x
5 0
3 years ago
Help ASAP!
Tema [17]

Answer:

B

Step-by-step explanation:

\boxed{area \: of \: sector =  \frac{1}{2} {r}^{2} θ }

Radius= diameter ÷2

r= 32 ÷2

r= 16

\frac{1}{2}  {r}^{2} θ =  \frac{512\pi}{3}

Substitute r= 16,

\frac{1}{2} ( {16}^{2} )(θ) =  \frac{512\pi}{3}

128 \: θ =  \frac{512\pi}{3}  \\ θ =  \frac{512\pi}{3}  \div 128 \\ θ =  \frac{512\pi}{384}

Divide the denominator and numerator by 128:

θ =  \frac{4\pi}{3}

Thus, the answer is B.

3 0
3 years ago
When coin 1 is flipped, it lands on heads with probability .4; when coin 2 is flipped, it lands on heads with probability .7. On
I am Lyosha [343]

Answer:

Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.

6 0
3 years ago
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