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3 years ago

1)Find the area of a parallelogram with base b and height h

Mathematics

1 answer:

Oksanka [162]3 years ago

8 0

Answer:

i got A

Step-by-step explanation:

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15 G F H 4) What is the value of x? A) 10 B) 12 C) 15 D) 17

coldgirl [10]

Answer:

C) 15

Step-by-step explanation:

This is an isosceles triangle (two of the three angles are equal) so two of the sides are also equal. x is the same length as 15.

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2 years ago

250 students in a high school senior class are surveyed about what majors they intend to declare in college. Of the 250 students

Vilka [71]

Answer:

Program C allows students to earn a Mathematics degree (B.A. or B.S.) by combining courses in the Department of Mathematics with courses from one other department. In most areas of specializations, mathematical and/or quantitative courses in other departments are part of the math degree program. All Program C students take a minimum of five core math courses: Calculus I, Calculus II, Calculus III, Introduction to Linear Algebra, and a proofs course, usually either Introduction to Abstract Algebra or Fundamental Properties of Spaces and Functions I.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Nita earns $20 per week walking her neighbor's dog. She also makes $2 per rose that she sells from her rose garden. Nita wants h

lyudmila [28]

Answer:

20+2>50

Step-by-step explanation:

4 0

3 years ago

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Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

Divide by $2$ both sides

$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

8 0

3 years ago

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If (a+bi)^2=2abi, what must be the relationship between a and b? Show or explain your reasoning.

Klio2033 [76]

$(a+bi)^2 =(a+bi)(a+bi)= a^2 +2abi+b^2 i^2 \\ \\ i^2 = -1 \\ \\ (a+bi)^2 = a^2-b^2 +2abi = 2abi \\ \\ a^2 -b^2 = 0 \\ \\ a^2 = b^2 \\ \\ a = b$

For the statement to be true, 'a' and 'b' must be equal

*First expand the binomial using FOIL, then set it equal to whats given "2abi".
Then you can find the relationship between a and b.

6 0

3 years ago