1)Find the area of a parallelogram with base b and height h

What is the discriminant of the quadratic equation, 4x^2-8x-5=0

uysha [10]

Answer:

Step-by-step explanation:

4x^2-8x-5=0

The discriminant is the number under the √. In this case it's 144

7 0

3 years ago

Read 2 more answers

Essay on a trip with friends

koban [17]

Step-by-step explanation:

click the photo there is answrr

5 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

Tim,Griff and Kay baked chocolate for Kay s birthday party.Tim baked 3 times as many as Kay.Griff baked half as many as Tim.Alto

lianna [129]

Answer: 48

------------------------------------------------------------------------------
Define the number of cakes they baked in term of x
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Let the number of cakes Kay baked be x

Kay = x
Tim = 3x   ← Tim baked 3 times as many as Kay
Griff = 1.5x   ← Griff baked 1/2 as many as Tim

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Construct the equation and solve for x
------------------------------------------------------------------------------
The total number of cakes baked was 88.

x + 3x + 1.5x = 88   ← Combine like terms
5.5 x = 88 ← Divide by 5.5
÷5.5   ÷5.5
x = 16

------------------------------------------------------------------------------
Find the number of cakes each baked
------------------------------------------------------------------------------
Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24

------------------------------------------------------------------------------
Answer: Tim baked 48 cakes.
------------------------------------------------------------------------------

3 0

3 years ago

How to get to the answer

Ilia_Sergeevich [38]

Answer:

$\large\boxed{C)\ F(x)=2^x+1}$

Step-by-step explanation:

$C)\ F(x)=2^x+1\\\\\text{Put the values of x from the table to the equation of a function:}\\\\F(3)=2^3+1=8+1=9\qquad\ CORREC\\F(4)=2^4+1=16+1=17\qquad CORRECT\\F(6)=2^6+1=64+1=65\qquad CORRECT\\F(7)=2^7+1=128+1=129\qquad CORRECT\\F(8)=2^8+1=256+1=257\qquad CORRECT$

7 0

3 years ago