Answer:
=![\sqrt[3]{49x^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B49x%5E%7B2%7D%20%7D)
Step-by-step explanation:
We have been given the expression;
7 times x to the two thirds power which can be written mathematically as;
To express the above expression as a radical, we need to recall that;
![a^{\frac{b}{n}}=\sqrt[n]{a^{b}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bb%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bb%7D%7D)
Therefore;
![(7x)^{\frac{2}{3}}=\sqrt[3]{(7x)^{2} }\\\\=\sqrt[3]{49x^{2} }](https://tex.z-dn.net/?f=%287x%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%287x%29%5E%7B2%7D%20%7D%5C%5C%5C%5C%3D%5Csqrt%5B3%5D%7B49x%5E%7B2%7D%20%7D)
Hey there! :)
Answer:
x = 1.117
Step-by-step explanation:
Graph the two equations:
p(x) = 5x² - 3
q(x) = 2x + 1
On the graph below, the positive point of intersection is at (1.117, 3.233).
Positive x-value = 1.117.
First off, do a prime factoring of the constant and leading coefficient, namely 9 and 8 respectively.
so a prime factoring of 8 is 2*2*2, and a prime factoring of 9 is 3*3.
so, those are the factors... now, how do we produce products that gives us the middle coefficient +18?
well, let's see hmmmm 2 * 3 * 3 and 2 * 3....so that's 18 + 6, that's 24.. .so... no good is not 18, let's try again.
2*2*3 and 2 * 3, so that's 12 + 6, now, that's +18
so we'll use those, 2*2*3 and 2*3, or 4 * 3 an 2 * 3, (4x + 3)(2x + 3) = 0.
<span>We have 2 given numbers:
=> 86 + 68 + 38 = 192
=> 68 + 38 + 86 = 192 also
This kind of process used commutative property system of equation in where:
a + b = b + a
No matter what sequence you are going to use, the answer would always be the
same.
In the given 2 equations, notice that both digits of 2 group of equation
contains the same number. The only difference is they were added with different
orders. Yet the answers are still the same.
</span>
Answer:
92kyroydyodpgxtzoggz
Step-by-step explanation:
2+92r
