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Alja [10]
3 years ago
10

Find the value of x in the polygon ​

Mathematics
2 answers:
laila [671]3 years ago
4 0
Use the Pythagorean theorem (a^2+b^2+x^2)
Evgesh-ka [11]3 years ago
3 0

x equals to 10.............

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Can someone can help me solve this inequality?
12345 [234]

Answer:

b < -10  and  (-∞, -10)

Step-by-step explanation:

I won't draw the number line but I will do the interval notation.

Interval notation is a way to describe infinite or finite sets with numbers.

To solve the inequality first add 2 to both sides to get:

-b > 10 Multiply both sides by -1:

b < -10 is the simplification of the inequality .

Now to write this in interval notation you need to know which direction the values are increasing, since b is less than -10, the values are going down starting from -10 (not including -10).

Interval notation: (-∞, -10)

6 0
3 years ago
What's the verbal expression for this ?
maria [59]
Four times a number to the second power divided by seven.
6 0
3 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
Please help me thanks
Mariulka [41]
The answer is D.

Since the two triangles are congruent, they would have equal angles.

The reason why the other answer choices are wrong...

A) ∠S is equal to ∠Y, not ∠Z.
The angle that is equal to ∠Z is ∠T.

B) Line ST is equal to Line YZ, not Line XZ.
The Line that is equal to Line XZ is Line RT.

C) Line RS is equal to Line XY, not Line ST.
The Line that is equal to Line ST is Line YZ.



Hope this helped! Brainliest is always welcome :)
8 0
3 years ago
Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles
mariarad [96]

Answer:

p_v =P(z>2.087) =0.0184

So with the p value obtained and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.  

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

\sigma=2.5

And the statistic is given by this formula:

z=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sigma\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}

Where z follows a normal standard distribution

The system of hypothesis on this case are:

Null hypothesis: \mu_c \leq \mu_t+1

Alternative hypothesis: \mu_c >\mu_t+1

Or equivalently:

Null hypothesis: \mu_c - \mu_t \leq 1

Alternative hypothesis: \mu_c-\mu_t>1

Our notation on this case :

n_c =45 represent the sample size for group control

n_t =45 represent the sample size for group  treatment

\bar X_c =5.2 represent the sample mean for the group control

\bar X_t =3.1 represent the sample mean for the group treatment

And now we can calculate the statistic:

z=\frac{(5.2-3.1)-(1)}{2.5\sqrt{\frac{1}{45}}+\frac{1}{45}}=2.087  

And now we can calculate the p value using the alternative hypothesis:

p_v =P(z>2.087) =0.0184

So with the p value obtained and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.  

5 0
4 years ago
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