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alex41 [277]
4 years ago
9

Rewrite the quadratic function in intercept or factored form f(x)=3x^2-12

Mathematics
1 answer:
melisa1 [442]4 years ago
3 0

Answer:

f(x)= 3(x - 2)(x + 2)

Step-by-step explanation:

The given quadratic function f(x) = 3x^2 - 12

Let's factor the given function.

f(x) = 3x^2 - 3*4

Here the common factor is 3, we can take it as common factor and write the remaining terms.

f(x) = 3(x^2 - 4)

Now we can factor (x^2 - 4) using the formula (a^2 - b^2) = (a-b)(a + b)

(x^2 -4) = (x^2 - 2^2)

= (x - 2)(x + 2)

Therefore, f(x) = 3(x^2 - 2^2)

f(x)= 3(x - 2)(x + 2)

Hope this will help you to understand the concept.

Thank you.


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There wasn't no pictures nor choices so I'm afraid that I had to look it up... The first link was from Brainly and "Tetianaalnasraween05" was asking the same question.

Original Figure: 6 and 3

'Similar' Figure(s):

1.) 4 and 2

2.) 10 and 4

3.) 6 and 6

Ratio of sides are 3/2 and 6/4, 6/4 could be simplified as 3/2, so as my guess, it is, 4 and 2

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I hope this helps, as always. I wish you the best of luck and have a nice day, friend..

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3 years ago
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lozanna [386]

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D. y =

Step-by-step explanation:

The solutions to this graph (meaning when y equals 0 or when the graph crosses the x-axis) are 4 and 5.

The only answer choice that has the solutions 4 and 5 when you factor it out is D.

Here's the proof:

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3 years ago
Based on information in the table, which equation can be used to model the relationship between x and y?.
Ivahew [28]

The relationship between y and x is y = 5x + 15.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are the variables, m is the rate of change (slope) and b is the initial value of y (y intercept).

From the table, using point (5, 40) and (25, 140):

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-40=\frac{140-40}{25-5} (x-5)\\\\y=5x+15

The relationship between y and x is y = 5x + 15.

Find out more on Linear equation at: brainly.com/question/14323743

8 0
2 years ago
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