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asambeis [7]
4 years ago
8

Force of 27N results in an acceleration of 3 m/s

Mathematics
1 answer:
solong [7]4 years ago
8 0
The image isn't clear enough for me to read, sorry. Also, isn't this physics?
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There was 2/3 of a pan of a lasagna in the refrigerator. Bill and his friends ate half of what was left. Write a number sentence
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Bill and his friends ate 1/3 of the pan, you get this by doing: 2/3 / 1/2 = 1/3 or 0.3333
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3 years ago
For each formula,rearrange so a is by itself:
vichka [17]

Step-by-step explanation:

a) 6-9b=3a

First:Subtract

3b=3a

Second: Devide

3b/3a

=(3÷3)(b÷a)

=1b/a

= b/a

B) 6b+2a=3a

First:Transpose (Group the like terms. signs will change.)

-3a+2a=-6b

=-1a=-6b

Second:Divide

=-1a/-6b:(-1÷-6)(a÷b)

=1a/6b

=a/6b

C)a/3=b+2

First: Transpose

a=3+2+b

=a/6+b

6 0
3 years ago
The manager of a coffee shop has one type of coffee that sells for $7 per pound and another type that sells for $11 per pound. T
kirza4 [7]
More of the $7 coffee would be used<span />
3 0
3 years ago
How many ways can you reflect ABCD onto itself
Irina18 [472]
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3 0
3 years ago
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
4 years ago
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