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Brut [27]
3 years ago
12

Think About the Process A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 17 pennies, ​12 dimes, and 26 qua

rters. The rest of the coins are nickels. There are 66 coins in all. How many of the coins are not​ nickels? If n represents the number of nickels in the​ jar, what equation could you use to find​ n?
_____ of the coins are not nickels.
Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

Number of coins that are not nickels = 55 coins

66 = 55 + n

number of nickels in the​ jar = 11

Step-by-step explanation:

Pennies = 17

Dimes = 12

Quarters = 26

Nickels = n

Total coins = 66

How many of the coins are not​ nickels?

= Pennies + Dimes + Quarters

= 17 + 12 + 26

= 55 coins

Number of coins that are not nickels = 55 coins

what equation could you use to find​ n?

Total coins = Pennies + Dimes + Quarters + nickels

66 = 17 + 12 + 26 + n

66 = 55 + n

n = 66 - 55

n = 11

number of nickels in the​ jar = 11

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100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a
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Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of P (M^{c} | V) is 0.70.

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(d) The value of P(V^{c}|M) is 0.625.

Step-by-step explanation:

It is provided that,

<em>V</em> = a student has a Visa card

<em>M</em> = a student has a Master card

N = 100, n (<em>V</em>) = 40, n (<em>M</em>) = 32 and n (<em>V</em> ∩ <em>M</em>) = 12.

The probability of a student having visa card is:

P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40

The probability of a student having master card is:

P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32

The probability of a student having  visa card and a master card is:

P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

P(A|B)=\frac{P(A\cap B)}{P(B)}

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. P (M^{c} | V) as follows:

P (M^{c} | V)=1-P(M|V)=1-0.30=0.70

Thus, the value of P (M^{c} | V) is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. P(V^{c}|M) as follows:

P(V^{c}|M)=1-P(V|M)=1-0.375=0.625

Thus, the value of P(V^{c}|M) is 0.625.

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