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stellarik [79]
2 years ago
5

If breadth of a cuboid is one-fourth of its length,height is 5cm and total surface area is 328 cm²,find the length and breadth o

f cuboid
​
Mathematics
1 answer:
velikii [3]2 years ago
3 0

The length of cuboid is 16 cm and breadth of cuboid is 4 cm.

<h3>How to find the Surface Area of Cuboid?</h3>

A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (L), Breadth (B), and Height (H) of the cuboid and use the formula, SA=2 x ( LB + BH + HL ) , to find the surface area.

Here, We have given that height of the cuboid is 5cm.

Let length of the cuboid = X cm

so, the breadth of the cuboid = \frac{X}{4} cm

also, we have given that total surface area is 328 cm²

Now, put all the values in the formula of Surface Area (SA):

SA = 2 x ( LB + BH + HL )

SA = 2 x ( X²/4 + 5X/4 + 5X )

SA = 2 x ( ( X² + 5X + 20X) / 4 )

SA = ( X² + 5X + 20X ) / 2

X² + 5X + 20X = 328 x 2

X² + 25X = 656

X² + 25X - 656 = 0

using Quadratic Formula: see the attached figure for the formula.

here Discriminant D = b² - 4ac

D = 625 - 4(-656)

D = 3249

on putting value of D or b² - 4ac in the formula we get

X =  ( -25 + 57 ) / 2 and ( -25 - 57 ) /2

length can not be negative so we eliminate the second answer.

now, X = 16 cm

breadth = X /4 = 4 cm

Hence, The length of cuboid is 16 cm and breadth of cuboid is 4 cm.

Learn more about " Quadratic Formula " from here: brainly.com/question/2615966

#SPJ9

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vichka [17]

For this case we must find the solution of the following equation:

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Add \frac {2} {3} to both sides of the equation:

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Luba_88 [7]
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8 0
3 years ago
PLEASE HELP! The AHS football team did a weigh-in at the start of training camp. The weights of the players were distributed nor
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<h3>Answer:  2.5%</h3>

=============================================================

Explanation:

Notice how 98-2*6 = 98-12 = 86. So we're 2 standard deviations below the mean.

Start at the center, which is where the highest point is located. The value 98 is at the center. Then move 2 spots to the left, which has us move 2 standard deviations lower than the mean, and we arrive at 86. Refer to the diagram below.

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