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marshall27 [118]
3 years ago
9

What is the speed of a 3 cm diameter roll if it has a velocity of 1220 yards/hour?

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

The speed of the roll is 1239.52 revolutions per minut (1239.52 rpm).

Step-by-step explanation:

In this problem we want to know the angular speed of the roll, knowing its tangencial speed (1220 yards/hour).

The relation between the angular speed and the tangencial speed is

v=\omega*r=\omega*(D/2)

\omega=2v/D

In this case we have a diameter of 3 cm and a velocity of 1220 yards/hour. So we can write

\omega=2v/D=2*1220\frac{yards}{hour} *\frac{1}{3\,cm} *\frac{91.44cm}{1 yard} *\frac{1hour}{60min}= 1239.52 \frac{1}{min}=1239.52 rpm

So the speed of the roll is 1239.52 revolutions per minut (1239.52 rpm).

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A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the
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Width of rectangle is 8.4 cm

Step-by-step explanation:

Length of rectangle = x+4

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Perimeter = 26 cm

We need to find width of rectangle.

The formula used is:

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Putting values and finding x first:

Perimeter=2(length+width)

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26=2(13x+4)

26=26x+8

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x=0.7

So, value of x is 0.7

Now width= 12x = 12(0.7)

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So, width of rectangle is 8.4 cm.

Keywords: Perimeter of Rectangle

Learn more about perimeter of rectangle at:

  • brainly.com/question/6564657
  • brainly.com/question/6594923
  • brainly.com/question/1822996

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Step-by-step explanation:

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