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faltersainse [42]
3 years ago
14

Help

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0

The equation of the line is y - 3 = 5(x - 8) ⇒ c

Step-by-step explanation:

The point-slope form of the linear equation is y-y_{1}=m(x-x_{1}) , where:

  • m is the slope of the line
  • (x_{1},y_{1}) is a point on the line

∵ The line passes through point (8 , 3)

∴ x_{1} = 8 and y_{1} = 3

∵ The slope of the line is 5

∴ m = 5

- Substitute these values in the form of the equation below

∵ y-y_{1}=m(x-x_{1})

∴ y - 3 = 5(x - 8)

The equation of the line is y - 3 = 5(x - 8)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

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What is the best approximation for the area of this circle?
butalik [34]

Area =113.0ft^2 . Correct option is D) 113.0 ft² .

<u>Step-by-step explanation:</u>

Here we have , A circle labeled with radius = 6 ft . We need to find the best approximation for the area of this circle . Let's find out:

We know that area of circle = \pi r^2 , We have following parameters as

Radius = r = 6 ft\\\pi = 3.14\\Area= \pi r^2 = ?

So , Area of circle is

⇒ Area =\pi r^2

⇒ Area =(3.14) (6)^2

⇒ Area =(3.14) (36)^

⇒ Area =113.04ft^2

On Rounding off

⇒ Area =113.0ft^2

Therefore , Area =113.0ft^2 . Correct option is D) 113.0 ft² .

5 0
3 years ago
Read 2 more answers
Plz help me with this math question
sergejj [24]

Answer:

8^2-60 ,   11^1   , 2^2x5

Step-by-step explanation:

2^2= 4

4 x 5 = 20

11^1= 11

8^2= 64

64-60 = 4

5 0
2 years ago
Anybody...Help!!!!!!!!!!!
Sloan [31]
Simple...

when they ask for the rate of change they ask for slope -->>

Using \frac{ y_{1} - y_{2} }{ x_{1} - x_{2} } to find the rate of change for (-3,0) and (-2,-5)

\frac{0--5}{-3--2}

\frac{0+5}{-3+2}

\frac{5}{-1}

m=-5 

Thus, your answer.


4 0
2 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

z^2=1\implies z=\pm1\implies x=y=\pm2

There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}

3 0
3 years ago
Compare and Contrast: Below are two equations. Solve each equation and compare the two solutions. Choose the statement that is t
grin007 [14]
Equation #1:
|2x - 3| = 17
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2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
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x = -7
The solutions are x = 10 or x = -7.

Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5

Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
    FALSE
b. Equation @1 has more solutions than Equation #2.
    TRUE
c. Equation #1 has fewer solutions than equation #2.
    FALSE
d. None of the statements a,b, or c apply.
    FALSE

Answer: b.

5 0
3 years ago
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