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zzz [600]
2 years ago
9

VJKL has vertices J (6,2), K (1,3), and

Mathematics
1 answer:
klio [65]2 years ago
8 0

Answer:

r3234r32r

Step-by-step explanation:

dfefedwfdsf4r36557tgrfdgdgfgreagf

dfefedwfdsf4r36557tgrfdgdgfgreagf

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Simplify. Assume that no denominator is equal to zero. <br><br> 4^12/4^5
Georgia [21]

Answer:

16,384 or 2^14

Step-by-step explanation:

4^12= 4*4*4*4*4*4*4*4*4*4*4*4=16,777,216

4^5= 4*4*4*4*4=1024

16,777,216/1024=16,384

16,384=2^14

4 0
3 years ago
Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.
-Dominant- [34]
Ugh, these questions.

21x^3y^4 + 15x^2y^2 - 12xy^3

3xy^2 (7x^2y^2 + 5x - 4y)

Clearing up clutter...

3xy² (7x²y² + 5x - 4y)

That's your answer.  Thanks for working my brain. ;)
6 0
3 years ago
Read 2 more answers
Create an inequality: <br><br> The sun of the numbers is not more than 12
lara31 [8.8K]

Answer:

x + y ≤ 12

Step-by-step explanation:

Inequality:

   Not more than 12 means less than or equal to 12

x + y ≤ 12

6 0
2 years ago
Find the first four terms of the sequence an = 4n-6
natulia [17]

Answer:

The first four terms of the sequence are-6, -2, 2 and 6

Step-by-step explanation:

The given sequence is a_n=4n-6

In order to find the first four term of the sequence we put n =0, 1, 2 and 3.

For n =0

a_0=4(0)-6=-6

For n =1

a_1=4(1)-6=-2

For n =2

a_2=4(2)-6=2

For n =3

a_3=4(3)-6=6

Therefore, the first four terms of the sequence are

-6, -2, 2 and 6

5 0
3 years ago
What is ten times ten
Snezhnost [94]
10x10=100 that the answer
8 0
3 years ago
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