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2 years ago

VJKL has vertices J (6,2), K (1,3), and

Mathematics

1 answer:

klio [65]2 years ago

8 0

Answer:

r3234r32r

Step-by-step explanation:

dfefedwfdsf4r36557tgrfdgdgfgreagf

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(Need help) (ASAP) Point: 18

Anastasy [175]

Answer:

Step-by-step explanation:

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2 years ago

I need help with these two .

stira [4]

Answer:

6 .Cant find the answer there

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2 years ago

A park has a length to width ratio of 7:4 and the perimeter of the park is 880 meters. What are the length and width of the park

Schach [20]

Step-by-step explanation:

Ratio of length to width = 7 : 4

length = 7x

width = 4x

7x + 4x = 11x

length = 880

$880 + 4x = 11x$

$880 = 11x - 4x$

$880 = 7x$

$\frac{880}{7} = x$

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width = 4x

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2 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

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2 years ago

A student weighs a sample of the shale and

tia_tia [17]

interesting choice of pfp

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2 years ago