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serious [3.7K]
3 years ago
7

Using a simulator at space​ camp, you practice landing your individual spaceship on landing platforms that have different shapes

. The score you get depends on the area of the platform. To find the area of this​ platform, divide it into a triangle and a parallelogram. Then find the area of each part and add.
A five-sided shape has a horizontal bottom of length 6 meters. The sides that extend from the bottom of the shape are parallel, the same length, and rise from left to right. The remaining sides extend from the upper ends of the parallel sides to form a vertex. The perpendicular distance from the base to this vertex is 7 meters. The perpendicular distance from the base to the upper left vertex is 4 meters.

Mathematics
1 answer:
Mila [183]3 years ago
3 0

The Area of the platform is 33m²

Step-by-step explanation:

As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m

Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m

Since the platform is five-sided, the figure can be broken down into constituting parts

  1. Parallelogram ║ABCE
  2. Δ DCE

Are of the figure= Area of ║ABCE+ area Δ DCE

Area of ║ABCE= breadth * height

= 6*4 ⇒24m ²

Area Δ DCE= ½*(base)(height)

Putting the value of base is 6m and height as 3m

Area Δ DCE= ½*6*3

=9m ²

Total area= 24+9= 33m ²

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Midpoint ( (x1+x2)/2, (y1+y2)/2)

      ( (5+-3)/2, (9+7)/2)

        (2/2,16/2)

   (1,8)

Answer: (1,8)


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3 years ago
Which statement is true about the product square root of 2(3square root of 2 + square root of 18)? 2
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√2(3√2+√18)=3*2+6=12

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Jason is shopping at a store for a shirt. He has a coupon that will reduce the original price of the shirt by $2. A 4% sales tax
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5 0
2 years ago
12. Find the measure of each interior angle of triangle QRT.
Veseljchak [2.6K]

Answer:

\angle QRT=125.6\°

\angle RTQ=6.4\°

\angle TQR=48\°

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle 17x is an exterior angle of the triangle QRT. Then:

17x=\angle RTQ+\angle TQR

Where:

\angle RTQ=2x\\\\\angle TQR=48\°

Substituting values and solving for "x", we get:

17x=2x+48\\\\17x-2x=48\\\\15x=48\\\\x=3.2

Then:

17x=17(3.2)=54.4\°\\\\\\\angle RTQ=2(3.2)=6.4\°

The sum of the interior angles of a triangle is 180°, therefore:

\angle QRT+\angle RTQ+\angle TQR=180

Solving for \angle QRT, we get:

\angle QRT=180-48-6.4=125.6\°

8 0
3 years ago
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