From what i see, i guess the answer may be B. it looks like it, but i dont really know.
Y – y1 = m(x – x1)
y-(-1)=-5(x-2)
Y+1=-5(x-2)
C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
they both small and Rocky
