(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)
… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))
… = -1/cos(2<em>x</em>)
Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.
G = - h/3 + 11/3
H = 11 - 3g
I hope this helps
Answer:
<u>108</u>
Step-by-step explanation:
Volume of a Square Pyramid :
- V = 1/3 x Base Area x Height
Solving :
- V = 1/3 x (6)² x 9
- V = 36 x 3
- V = <u>108</u> cubic centimeters
Answer:
Step-by-step explanation:
Answer: -56 -17 0 5 34
Step-by-step explanation:
The more left you go on a number line the smaller it is
