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KiRa [710]
3 years ago
14

What is the value of y in the following system of equations? explain how you found your answer

Mathematics
2 answers:
AlekseyPX3 years ago
7 0

Step-by-step explanation:

I've used elimination method over here but it can also be done by using substitution.

Andreyy893 years ago
5 0
2x + 3y = 6
2x + y = -2

Solve the second equation for y and substitute into the first equation

2x + y = -2
y = -2x - 2

2x + 3y = 6
2x + 3(-2x - 2) = 6
2x - 6x - 6 = 6
-4x - 6 = 6
-4x = 12
x = -3

Plug back in to solve for y
2x + y = -2
2(-3) + y = -2
-6 + y = -2
y = 4

Plug into other equation to check
2x + 3y = 6
2(-3) + 3(4) = 6
-6 + 12 = 6
6 = 6 :)
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Solve 5x 2 - 7x + 2 = 0 by completing the square. What are the solutions?
Alexeev081 [22]

Answer:

x=\frac{2}{5} or x=1

Step-by-step explanation:

The given quadratic equation is

5x^2-7x+2=0

Group the constant terms on the right hand side.

5x^2-7x=0-2

5x^2-7x=-2

Divide through by 5.

x^2-\frac{7}{5}x=-\frac{2}{5}

Add the square of half the coefficient of x., which is (\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100} to both sides of the equation.

x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}

The left hand side is now a perfect square.

(x-\frac{7}{10})^2=\frac{9}{100}

Take the square root of both sides;

(x-\frac{7}{10})=\pm \sqrt{\frac{9}{100}}

x-\frac{7}{10}=\pm \frac{3}{10}

x=\frac{7}{10}\pm \frac{3}{10}

x=\frac{7-3}{10} or x=\frac{7+3}{10}

x=\frac{4}{10} or x=\frac{10}{10}

x=1 or x=\frac{2}{5}

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3 years ago
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Answer:

A

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4(2x+3)=x(3+5)+12<br> Help
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Answer:

Step-by-step explanation:

8x + 12 = 3x + 5x + 12

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Bringing like terms on one side

8x - 8x = 12 - 12

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The value of 4q+2q is 30
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