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fgiga [73]
3 years ago
15

1/4 of febuary = ....... days

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0
There are 28 days in February. Divide 28 by 4 and the answer is 7 days
daser333 [38]3 years ago
7 0
February has 28 days. First, you would have to divide 28 by 4.

28 divided by 4 is 7.

The answer would be 7 days.
You might be interested in
the admission fee for a charity event is $7 for children and $10 for adults the event was attended by 700 people on the total am
9966 [12]

Answer:

there were 200 children and 500 adults at the show

Step-by-step explanation:

7x+10y=6400

x+y=700

x=700-y

7(700-y)+10y=6400

4900-7y+10y=6400

-7y+10y=1500

3y=1500

y=500

x=700-y

x=700-500

x=200

3 0
2 years ago
Read 2 more answers
Solve the following inequality: 3-5x-x^2>=0
Dennis_Churaev [7]

Answer:

-5/2+-1/2√37≤x≤-5/2+1/2√37

Step-by-step explanation:

Step 1: Find the critical points

-x^2-5x+3=0

For this equation: a=-1, b=-5, c=3

−1x^2+−5x+3=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(−1)(3)/2(-1)

x=5±√37 /−2

x=-5/2+1/2√37

Step 2: Check intervals in between critical points

x≤-5/2+1/2 √37 (Doesn't work in original inequality)

-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)

x≥-5/2+1/2 √37 (Doesn't work in original inequality)

5 0
3 years ago
In the number 555,55 each digit is a 5 but value of rachis different based on its place in the number. How does the value of 5 i
andrew11 [14]
As you move from each place to the left one place, the value increases by 10. If you move right a place, the value decreases by 10.

5 0
3 years ago
In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen
fenix001 [56]
Let
 x = number of common cars
 y = number of suvs
 we can write the following system of equations
 x-y = 12
 x = 1.429y
 Solving the system we have
 x-y = 12
 1.429y-y = 12
 and (1,429-1) = 12
 y = (12) / (1,429-1) = 27.97202797
 then,
 x = 1429 * (27.97202797)
 x = 39.97202797
 answer
 The number of suvs in the parking lot is 28
6 0
3 years ago
Use the definition of logarithm to simplify each expression.
konstantin123 [22]
1)\ \ \ log 10 ^{10}=x\ \ \ \Leftrightarrow\ \ \ 10^x=10^{10}\ \ \ \Leftrightarrow\ \ \ \ \ \ x=10\\\\2) \ \ \ log 10 ^{100}=x\ \ \ \Leftrightarrow\ \ \ 10^x=10^{100}\ \ \ \Leftrightarrow\ \ \ x=100\\ \\ 3)\ \ \ log 10 ^ {10-4}=x\ \ \ \Leftrightarrow\ \ \ 10^x=10^{10-4}\ \ \ \Leftrightarrow\ \ \ x=6
7 0
3 years ago
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