The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.
Ways of having 17:
Die 1 Die 2 Die 3 sum
6 6 5 6+6+5 = 17
6 5 6 6+5+6 = 17
5 6 6 5+6+6 = 17
Those are the only 3 possibilities of having 17 (you can only loose 1 point).
The total number of outcomes are 6*6*6 = 216
So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139
<span>(r^2+7r+10/3) * (3r-30/r^2-5r-50)
1/3(3r^2+21r+10) x 3(r-10)/(r^2-5r-50)
(3r^2+21r+10)x(r-10)/(r^2-10r+5r-50)
(3r^2+21r+10)x(r-10)/(r-10)(r+5)
3r^2+21r+10/(r+5)
</span>
V = Displacement / Time
V = 5 m / 15 s
V = 1/3 m/s or 0.33 m/s
Answer:
3/4 or 0.75
Step-by-step explanation:
Answer:
36.36 (Repeating bar over the decimal .36)
Step-by-step explanation:
