It can be read as "six cubed."
It can be read as "six to the power of three."
It has a base of 6.
It is the same as multiplying three factors of 6.
It has an exponent of 3.
Have a Nice Day
Answer:
d. ∆UVW ∼ ∆UWT ∼ ∆WVT
Step-by-step explanation:
Two triangles are similar if the corresponding angle are congruent and if the ratio of the corresponding sides are proportional.
The logic is in three scenarios. The Cases that lead to similarities in a triangle can be expressed as follows
i. If two sides of a triangle are in the same ratio to the corresponding side of another triangle and the included angle are the same.
ii. If the three corresponding sides are in the same ratio then the triangles are similar.
iii. Also if the angles are of a triangle is congruent to the corresponding angles of another triangles they are similar.
Answer:
398
Step-by-step explanation:
She will have to score exactly 398 to tie the score with Anne
Answer:
47 and the median
Step-by-step explanation:
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
