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Anika [276]
3 years ago
11

What is 100 divided by 25​

Mathematics
2 answers:
Maslowich3 years ago
6 0
The answer would be 4
koban [17]3 years ago
5 0

Answer: the correct answer is 4

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The polynomial function f(x) is a fourth degree polynomial. Which of the following could be the complete list of the roots of f(
cluponka [151]

Answer:

the answer is A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The numbers x and y are inversely proportional. When the sum of x and y is 42, x is twice y. What is the value of y when x = -8?
dolphi86 [110]

Answer:

y= -4

Step-by-step explanation:

x+y=42.   We know that x plus y equals 42.

x=2y .   We also know that x equals twice y.

2y+y=42.   Since we know that x=2y, we're going to replace x with 2y from the original equation, simplified would be 3y=42.

y=14.   3y=42 simplified is y=14, this is because we divided both sides by 3 (since 3 and 42 are both divisible by 3) (btw divisible by 3 simply means that it can be divided by 3)

x+14=42.   Now that we know what y equals, let's replace y with 14 from the original equation.

x=28.  Now that we know that x=28 and y=14, we know that y is always x/2.

When x=-8, we divide it by 2 and get, -4.

Not absolutely positive as this was all mental math, but hope this helps! :)

4 0
4 years ago
I REALLY NEED HELP, PLEASE HELP !! WORTH 30 POINTS !!
valina [46]

Answer:

2/9

Step-by-step explanation:

y=6(3)^x

Let x =-3

y = 6 * 3^-3

Remember negative exponents move it from the numerator to the denominator

y = 6 *1/3^3

y = 6 * 1/27

y = 6/27

y = 2/9

8 0
4 years ago
Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices
Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt

Where P, Q are scalar functions

We want to compute

\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths \large C_1,C_2,C_3,C_4 which represents the sides of the rectangle.

\large C_1 is the line segment from (0,0) to (5,0)

\large C_2 is the line segment from (5,0) to (5,1)

\large C_3 is the line segment from (5,1) to (0,1)

\large C_4 is the line segment from (0,1) to (0,0)

Then

\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize \large C_1 as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

\large \displaystyle\int_{C_1}xydx+x^2dy=0

 Now the second integral. We parametrize \large C_2 as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25

The third integral. We parametrize \large C_3 as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2

The fourth integral. We parametrize \large C_4 as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

\large \displaystyle\int_{C_4}xydx+x^2dy=0

So

\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2

Now, let us compute the value using Green's theorem.

According with this theorem

\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx

where A is the interior of the rectangle.

so A={(x,y) |  0≤ x≤ 5,  0≤ y≤ 1}

We have

\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x

so

\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2

3 0
3 years ago
Which expression shows the first step in simplifying 2x – 3(x + 2y) – 5(y – 7x)?
artcher [175]

Answer: Option 3.


Step-by-step explanation:

1. To simplify the expression shown in the problem, the first step is to apply the Distributive property, this means that you must multiply the number that are outside of the parentheses by the numbers inside of them.

2. Then, you have that the first step is:

2x-3(x+2y)-5(y-7x)=2x-3x-6y-5y+35x

3. Therefore, you can conclude that the correct answer is the third option.


5 0
3 years ago
Read 2 more answers
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