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ella [17]
4 years ago
15

Can someone please help me with the evens, thank you!

Mathematics
1 answer:
lbvjy [14]4 years ago
5 0
Which ones do u need help on? 
all?
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Which is the best estimate for 6,193 ÷ 48 using compatible numbers.
Gala2k [10]
It would be B. 120 you would usually round up but the closest one to 129.02083 is 130 and since there is no 130 it would be 120
8 0
3 years ago
Read 2 more answers
Help pleaseee :) tyy
STatiana [176]

Answer:

The slope is 4

Step-by-step explanation:

First we pick 2 points (x, y):

(0, -2) and (1, 2)

Then, we use the slope (m) formula:

m = (y2 - y1)/(x2 - x1)

Given:

y2 = 2

y1 = -2

x2 = 1

x1 = 0

Work:

m = (y2 - y1)/(x2 - x1)

m = (2 + 2)/(1 - 0)

m = 4/1

m = 4

8 0
2 years ago
Select all the examples of categorical data. colors number of siblings favorite pet profits genre of music
bulgar [2K]

Answer:

Color, favorite pet, genre of music

Step-by-step explanation:

Categorical variables are simply statistical variables which are non - numeric, usually employed in characterization and groupings based on a certain number of fixed attributes, categories. In the options atated above, the categorical variables fall under a heading with a limited and fixed attributes such as color, pet and genre of music. However, options such as number of siblings and profit are purely numeric variables which can take up any numeric digits and allow for direct numeric computation. They are called quantitative variables.

3 0
4 years ago
-7x^3-9x^2+8x this is factoring completely
loris [4]
Answer:
<span> (x + 6) • (x + 5) • (x - 2)

Is this what u were looking for? Sorry if not XDD

</span>
3 0
3 years ago
Read 2 more answers
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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