3 years ago

Can someone please help me with the evens, thank you!

Mathematics

1 answer:

lbvjy [14]3 years ago

5 0

Which ones do u need help on?
all?

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I will give BRAINLIEST to the correct answer

erica [24]

Answer:

<PCH+<HCK=180-DEGREE BEING IN A STRAIGHT LINE.

3M+58+8M+155=180

11M=180-213

11M=-33

M=-3

SO,

<PCH

3M+58

=3*(-3)+58

=58-9

=49-DEGREE

7 0

3 years ago

PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!

svetlana [45]

We know in these kind of triangles that have a 90 degrees angle, we can do:

${a}^{2} + {b}^{2} = {c}^{2}$

so the first question:

$\sqrt{ {99}^{2} + {20}^{2} } = 101$

and then:

$b = \sqrt{ {17}^{2} - {15}^{2} } = 8$

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

$\frac{ \sqrt{15} }{ \sqrt{15} } = 1$

so , now multiply:

$\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}$

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,